Balance the following equation using the set of smallest whole-number coefficients. What is the sum of these coefficients? (be sure to include coefficients of "1" in the sum ). ____PbO + ___NH3 ---> ___Pb + ___N2 + ___H2O
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Balance the following equation using the set of smallest whole-number coefficients. What is the sum of these coefficients? (be sure to include coefficients of "1" in the sum ).
____PbO + ___NH3 ---> ___Pb + ___N2 + ___H2O
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- TTTTT 3. Jeanette wants to prepare a 0.125 mol/L solution of sucrose C12H22O11. The desired volume Jeanette wants to make is 50 ml. Formula Mass= Volume (L)= Moles Sucrose = Mass Sucrose= 0.050 L of water (solvent) ? Mass of Sucrose Formula Mass= Volume (L) - Moles LI SO Mass Li₂SO. = Mass of 0.050 L of 0.125 mol/L Sucrose 4. Grover wants to prepare a 6.00 mol/L solution of Li,SO.. The desired volume Grover wants to make is 500 ml. Li-SO Show work in this space SLIVEWORKSHEETS Show work in this space1. Balance the following chemical reaction: C2H5OH + 02 --> co2 + H20 2. Balance the following chemical reaction: NH3 + 02 --> N2 + H20 Answers or coefficients are whole numbers. Do not write fractions or decimals. 3. QUESTION 3 Balance the following chemical reaction: N2 + H20 --> NH3 + NO Answers or coefficients are whole numbers. Do not write fractions or decimals.ity 7 Problem-Solving! ctions: Show your solution in the space provided. Follow the GFFSA (Given, Find, omula, Solution, Answer) format if possible. Write your answers in the space provided. (5 points each) 1. Combustion of hydrocarbons like methane (CH4) produces two products, water (H2O) and carbon dioxide (CO2). Consider the chemical equation of this combustlon: CH4 + 2 02- CO2 + 2 H20, when 4 mol of CHa reacts with 4 mol of O2, how many moles of CO2 are formed? What is the limiting reactant? 2. How many grams of lead II chloride are produced from the reaction of 16.2 g of NaCl and 62.0 g of Pb(NO3)27 What is the limiting reactant? How much excess is left over?
- 2-1. Write and balance the equation if provided; Use the coefficients to write the molar ratios (aka stoichiometry) among substances involved in the equation. i.e., Balanced equation: x A + y B z C, Stoichiometry: x mol A = y mol B = z mol CBalanced equation:_____ H2 (g) + _____ N2 (g) → _____ NH3 (g)Stoichiometry (molar ratios):______ mol H2 ______ _____ N2 ______ ______ NH3Aktiv Chemistry < + C X b Success Confirmation XM Your Chemistry answe x app.101edu.co Answered: A 0.660 M X b Answered: How many × b Answered: A student X Time's Up! What quantity in moles of NaOH are there in 82.0 mL of 0.300 M NaOH? 1 4 7 +/- 2 5 8 New Tab mol 3 6 9 G 0 x + Submit X C x 100Hi! I am having difficulty finishing and finding out the rest of tables in excel. I am trying to find the Calcium Carbonate in an Eggshell. I have put up the excel sheet I have done with the given data already inputed, I just need to find out the rest. Thank you so much!
- balance this 2Al+2KOH+4H2SO4+24H2O----> ASApp 10 mins← X g 單 0 Priva Tern C My Account - MySam - Sam Hou X Content X Q mathway calculator - Search https://shsu.blackboard.com/ultra/organizations/_202946_1/cl/outline LI Lets start with the medical components. We need to determine how many units of the syringe connections can be made out of one metric ton of PEI, or around 2205 lbs of the plastic. X M Mathway | Basic Math Problem S X + 1 metric ton = 2205 lbs Starting material - PEI 1 metric ton ≈ 2205 lbs Calculation for number of units of each component: total weight of starting material PEI X Products Medical components Stopcock with Luer Connection, 1-way, male lock unit weight 2.72 g = 3/500 lbs 1 unit of medical component 1 weight of unit of component This calculation assumes all starting material is used during the production of the components. Medical components Products Stopcock with Luer Connection, 1-way, male lock unit weight 2.72 g 3/500 lbs Female Luer Lock 3/16" unit weight 0.63 g 7/5000 lbs Units = If necessary round to the…Balance the following equation. The coefficients are in order for the substances from left to right. "1" is a place holder for a spot that you would typically leave blank. T/I _C4H10 + __0₂ _CO₂ + 1,7,6,5 2, 9, 8, 10 O2, 8, 6,5 1, 7, 4, 5 O2, 13, 8, 10 _H₂O
- DATA: weight of the crucible + lid (Worucible Hid) =30.4265 weight of the crucible + lid + magnesium (Worucibletlid+Mg) =30.6831 weight of the product + crucible + id (Werucible-tid+Mg 0) =30.7168 mass of the product (mmgo) = ?/ CALCULATIONS: Mass of magnesium: mMg = Mass of oxygen: mo = Number of moles of Mg: Number of moles of O: no = Mole ratio of Mg to O in the compound: Mg / no = Empirical (simplest) formula of the compound:taprect number of significant figures. A. Precipitation of CaC,O4H,O from the Calculation Zone Salt Mixture mil o 3. Mass of salt mixture (g) Data Analysis, 1. 0.879 4. Mass of filter paper (g) 1.896 5. Mass of filter paper and CaC,O4•H2O (g) рaper 2.180 6. Mass of air-dried CaC,O4•H,O (g) B. Determination of Limiting Reactant Data Analysis, 3. 1. Limiting reactant in salt mixture CaCl, 2H,O 2. Excess reactant in salt mixture Data Analysis e cxbcipuu 1. Moles of CaC,O,'H,O precipitated (mol) Data Analysis, 4. Show calculation. 2. Moles of limiting reactant in salt mixture (mol) 20 See equation 8.1. 3. Mass of limiting reactant in salt mixture (g) Show calculation. trotanjl Data Analysis, 5. 4. Mass of excess reactant in salt mixture (g) Equals mass of salt mixture minus mass of limiting reactant. Show calculation. 5. Percent limiting reactant in salt mixture (%) Show calculation. 6. Percent excess reactant in salt mixture (%) rtc beccib For Trials 2 and 3, the percent CaCl,-2H,O in the…Determine the mass of chlorine in the original sample as the difference in mass between the anhydrous sample (after drying in the crucible) and the mass of copper. From the mass of chlorine, determine the moles of Cl. J Mass of clean, dry crucible + lid (g): Mass of crucible + lid + copper chloride (g): Mass of crucible + lid + anhydrous copper chloride (g): Record any observations, particularly color change. The copper chloride took 3 minutes and 10 second to turn from a bright blue green color to a burnt brown color. Once the copper chloride turned brown we heated it for 2 additional minutes to make sure everything was properly heated and all the water was removed from the copper chloride. Part III (B) Mass of copper + watch glass (g): Weigh 1 Weigh 2 Weigh 3 29.667 30.751 30.519 46.555 Mass of copper solid (g) 4.657 4.647 4.647