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Balance the following chemical equation (if necessary): 2 C₂H₂(g) + 15 O₂(g) → 10 H₂O 10 CO 10 2

Balance the following chemical equation (if necessary): 2 C₂H₂(g) + 15 O₂(g) → 10 H₂O 10 CO 10 2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Balancing Chemical Equations When balancing chemical reactions, it is critical to ensure that the number of atoms of each element in the reactants matches the number of atoms of those same elements in the products. This is based on the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a closed system. Consider the following chemical equation to be balanced: \[ \text{Balance the following chemical equation (if necessary):} \] \[ 2 \text{C}_5\text{H}_{10} \,(g) + 15 \text{O}_2 \,(g) \rightarrow 10 \text{H}_2 \text{O} + 10 \text{CO}_2 \] ### Step-by-Step Process: 1. **Identify the number of atoms of each element on both sides of the equation:** - **Left Side (Reactants):** - Carbon (C): \( 2 \times 5 = 10 \) atoms - Hydrogen (H): \( 2 \times 10 = 20 \) atoms - Oxygen (O): \( 15 \times 2 = 30 \) atoms - **Right Side (Products):** - Hydrogen (H): \( 10 \times 2 = 20 \) atoms - Oxygen (O): \( 10 \times 1 = 10 \) atoms (from H\(_2\)O) + \( 10 \times 2 = 20 \) atoms (from CO\(_2\)) = 30 atoms total - Carbon (C): \( 10 \times 1 = 10 \) atoms 2. **Verify the balance:** - The number of Carbon (C) atoms on the left is 10 and on the right is also 10. - The number of Hydrogen (H) atoms on the left is 20 and on the right is also 20. - The number of Oxygen (O) atoms on the left is 30 and on the right is also 30. Since the number of atoms for each element is the same on both sides of the equation, the equation is already balanced. ### Conclusion: The chemical equation: \[ 2 \text{C}_5\text{H}_{10} \,(g) + 15 \text{O}_2 \,(g) \
Transcribed Image Text:### Balancing Chemical Equations When balancing chemical reactions, it is critical to ensure that the number of atoms of each element in the reactants matches the number of atoms of those same elements in the products. This is based on the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a closed system. Consider the following chemical equation to be balanced: \[ \text{Balance the following chemical equation (if necessary):} \] \[ 2 \text{C}_5\text{H}_{10} \,(g) + 15 \text{O}_2 \,(g) \rightarrow 10 \text{H}_2 \text{O} + 10 \text{CO}_2 \] ### Step-by-Step Process: 1. **Identify the number of atoms of each element on both sides of the equation:** - **Left Side (Reactants):** - Carbon (C): \( 2 \times 5 = 10 \) atoms - Hydrogen (H): \( 2 \times 10 = 20 \) atoms - Oxygen (O): \( 15 \times 2 = 30 \) atoms - **Right Side (Products):** - Hydrogen (H): \( 10 \times 2 = 20 \) atoms - Oxygen (O): \( 10 \times 1 = 10 \) atoms (from H\(_2\)O) + \( 10 \times 2 = 20 \) atoms (from CO\(_2\)) = 30 atoms total - Carbon (C): \( 10 \times 1 = 10 \) atoms 2. **Verify the balance:** - The number of Carbon (C) atoms on the left is 10 and on the right is also 10. - The number of Hydrogen (H) atoms on the left is 20 and on the right is also 20. - The number of Oxygen (O) atoms on the left is 30 and on the right is also 30. Since the number of atoms for each element is the same on both sides of the equation, the equation is already balanced. ### Conclusion: The chemical equation: \[ 2 \text{C}_5\text{H}_{10} \,(g) + 15 \text{O}_2 \,(g) \
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