BaCO3 - Ba2+ + CO3? reaction was given.It is known that the carbonate anion is hydrolyzed in[HCO ][OH][co? ]CO3- + H20 = HCO; + OH Kb1and[H2CO3][OH¯][HCO3]HCO; + H2O = H;CO3 - OH- Kb2 =form.Since Ka1 = 1.44x10-7, Ką2 = 4.7x10-11 and KspBaco3 = 5.1x10-9, calculate the solubility ofBaCO; salt at pH = 8 and 12 depending on the pH value.

Given: pH = 8 and 12 Ka1 = 1.44×10-7 Ka2 = 4.7×10-11 Ksp of BaCO3 = 5.1×10-9

BaCO3 = Ba-* + CO3² reaction was given. It is known that the carbonate anion is hydrolyzed in CO3 + H;O = HCO; + OH Kb1 [HCO3][0H¯] and HCO; + H20 = H;CO3 - OH Kb2 [H2CO3][OH¯] form. [HCO] Since Kg1 = 1.44x10-7, K2 = 4.7x1011 and KepBaco3 = 5.1x10-9, calculate the solubility of %3D BaCO; salt at pH = 8 and 12 depending on the pH value.

BaCO3 = Ba-* + CO3² reaction was given. It is known that the carbonate anion is hydrolyzed in CO3 + H;O = HCO; + OH Kb1 [HCO3][0H¯] and HCO; + H20 = H;CO3 - OH Kb2 [H2CO3][OH¯] form. [HCO] Since Kg1 = 1.44x10-7, K2 = 4.7x1011 and KepBaco3 = 5.1x10-9, calculate the solubility of %3D BaCO; salt at pH = 8 and 12 depending on the pH value.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

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BaCO3 - Ba2+ + CO3? reaction was given.
It is known that the carbonate anion is hydrolyzed in
[HCO ][OH]
[co? ]
CO3- + H20 = HCO; + OH Kb1
and
[H2CO3][OH¯]
[HCO3]
HCO; + H2O = H;CO3 - OH- Kb2 =
form.
Since Ka1 = 1.44x10-7, Ką2 = 4.7x10-11 and KspBaco3 = 5.1x10-9, calculate the solubility of
BaCO; salt at pH = 8 and 12 depending on the pH value.

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