(B2). Implement a randomized Skip-List with operations Insert(), Delete() and Search(). Your program should read from the input file just like in (BI). Print out the skip-list using the format given below 16 16 71 91 2 16 71 89 91 2 10 15 16 31 71 86 89 91 96 15 16 131 71 89

(B2). Implement a randomized Skip-List with operations Insert(), Delete() and Search(). Your program should read from the input file just like in (BI). Print out the skip-list using the format given below 16 16 71 91 2 16 71 89 91 2 10 15 16 31 71 86 89 91 96 15 16 131 71 89

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, for example: 0, 1, 1, 2, 3, 5, 8, 13. Complete the fibonacci() function, which takes in an index, n, and returns the nth value in the sequence. Any negative index values should return -1 Ex: If the input is: 7 the output is: fibonacci (7) is l3 Note: Use recursion and DO NOT use any loops.
Suppose you are given a vector x. Write first a pseudo-code or algorithm that would print out the sum of all the entries in x. You will probably want to use a some kind of for loop construction to achieve this. 1: for i = start : finish do 2: statements 3: end for Now use the start:increment:finish notation, and modify your procedure slightly, to print out the sum of the odd elements in the array (that is, the elements in entries 1, 3, 5, and so on). Implement and test your algorithm with an arbitrary array of real numbers using Python.
Consider the following code fragment.Trace the code and for each iteration of the while loop write the updated values of x and y. What does this code finally print out on lines 10 and 11?
Experiment 1: IMPLEMENTATION OF CAESAR CIPHER Objective: To implement the simple substitution technique named Caesar cipher using C+ language. Theory: To enerypt a message with a Caesar cipher, each letter in the message is changed using a simple rule: shift by three. Each letter of the message is shifted a fixed distance (3 for example) down the alphabet, A becomes D, B becomes E, and so on. For the last letters, we can think of alphabet as a circle and "wrap around", W becomes Z. X becomes A, Y becomes B, and Z becomes C. To change a message back, cach letter is replaced by the one three before it. Example ABCDEFGHIJKLMNOPQRSTUVWXYZ t t t t t t t t ttt t t t t t t tt t t t t t t ft DEFGHIJKLMNOPQRSTUVW XY Z ABc) digorithm STEP-1: Read the plain text from the user. STEP-2: Read the key value from the user. STEP-3: If the key is positive then encrypt the text by adding the key with each character in the plain text. STEP-4: Else subtract the key from the plain text. STEP-5: Display the…
The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, for example: 0, 1, 1, 2, 3, 5, 8, 13. Complete the Fibonacci() function, which has an index, n, as parameter and returns the nth value in the sequence. Any negative index values should return -1. Ex: If the input is: 7 the output is: Fibonacci(7) is 13 Note: Use a for loop and DO NOT use recursion.
create an array of 30 random numbers that range between 1and 100. And yet again, write a function that will receive a number from the userand determine if that number exists in the array or not. But this time, start bySORTING your input list. After a sort, the list in problem 1 is as follows:[2, 2, 3, 5, 12, 14, 14, 15, 23, 36, 39, 41, 44, 44, 45, 48,49, 50, 52, 52, 59, 71, 81, 82, 88, 89, 89, 93, 96, 97] Approach: Implement a method called findC(x, A, i, j), where x is the number we arelooking for in array A, the first index of the array is i and the last index is j. We wantto determine whether x exists in A anywhere between index i and index j. Your firstcall to this method will therefore look like this: findC(x, A, 0, A.length-1). In the body of your function, compare x with the item that is in the middle of thearray, as you did before. As before, call the middle of index of the array mid. But thistime, if x<=a[mid], recursively call your function to search ONLY the first half of…
In mathematics, the harmonic series is the divergent infinite series: 1 1 1 + 1 1 1 +.... + + n n=1 4 Write a MATLAB function M-file, HarmArray , to 1. Input a positive integer, last 2. Use a for loop to create & return as output an array x , that contains the harmonic sequence 3. Preallocate the x array 4. Do not allow input to be an array. Example if last = 5, then x would be [1, 1/2, 1/3, 1/4, 1/5] >>HarmArray(5) ans 1.0000 0.5000 0.3333 0.2500 0.2000 - IN
Create Java Program of an array of Strings which are initialized to the 7 days of the week. Using while-loop, do-while, and for-loop to print all the contents of the array.
Complete the function encrypt, which takes an unencrypted, plaintext message called plaintext and encrypts it according to the following algorithm. The function then returns the encrypted ciphertext message. 1. Using a for-loop, swap the character at each even-indexed position with the one to its right. (Examples: abcdefg becomes badcfe; abcdefg becomes badcfeg) You'll have to carefully accomodate for even-lengthed and odd-lengthed strings. 2. Then, using another for-loop, replace every uppercase letter with its lowercase equivalent, and replace every lowercase letter with its uppercase equivalent. 3. (May be combined with the loop in the previous step in the code.) Except for the character o, replace each digit character with 10 minus that digit. (Examples: 2 becomes 8, 9 becomes 1.) Hint: use ord and/or chr and/or str and/or int instead of a 10-way if- statement! Examples: Function Call encrypt('abCDefGHIJKLMnopQ') encrypt('ABCdefGHIjkL') encrypt('0123456789') encrypt('123456789')…
Extend the below program such that when reading the 3 values per record from the file, the values get stored in arrays. We need an array for each data type read per record ( loop counter to store corresponding values at the same index in the 3 different arrays). We need a two dimensional char array. when copying a string to another, we need to use the strncpy function. Once all the data from the input file is read and stored this data into the 3 arrays, open a file for writing ( output.csv) and print the array data to this file (use fprintf). The format written to the file should be one line per record, with each field separated by a comma (‘,’). Close both files. #include<stdio.h> char c; int main (int argc, char **argv) { FILE* f; if (argc != 2) { printf("No filename in the argument"); return 1; } f = fopen(argv[1], "r"); if (f == NULL) { printf("The file cannot be opened successfully: %s\n",argv[1]); return 1; }…
Using a csv file attached (https://file.io/NMvbdnv4E3r0), Create a program on python that use the csv file. The program should accept a user's input of a compound. It should output the molar mass (in 2 decimal places only) of the compound.by using the csv file to compute for the atomic mass at name of the elements. Furthermore, if the "elements involved" are wrong an invallid message should be outputted and only existing chemical symbols are the output. The same goes for wrong input of the "number of atoms" wherein a wrong an invallid message should be outputted and only integers are to be inputted by the user. Program should look like this: Enter compound: C6H12O6 Enter elements involved: C,H,O Enter no. of Carbon atoms: AA Enter no. of Hydrogen atoms: 12 Enter no. of Oxygen atoms: 6 Wrong input of number of atoms! Try again. or Enter compound: C6H12O6 Enter elements involved: C,H,O Enter no. of Carbon atoms: 6 Enter no. of Hydrogen atoms: 12 Enter no. of Oxygen atoms: 6…
You are now running the insertion sort algorithm on your computer. Assume that at the start of iteration j=4 of the for loop, the array A is A=3,6,8,4,9,2,7,10, and that the for loop is iteration j=4. The array A should be written at the beginning of iteration j=5 of the for loop.