b). What is the conjugate base of NH4? c) The Ka for NH4* is 5.5x10-10. What is the pKa for its conjugate base? pKa= d) AlCl3, when dissolved in water, forms a(n) (basic or acidic) solution (Circle one). Calculate the pH at the equivalence point for the titration of 0.120 M hydrofluoric acid (HF) with 0.120 M NaOH. The K, of HF is 6.8×104. (Know how to do both acid and base)
b). What is the conjugate base of NH4? c) The Ka for NH4* is 5.5x10-10. What is the pKa for its conjugate base? pKa= d) AlCl3, when dissolved in water, forms a(n) (basic or acidic) solution (Circle one). Calculate the pH at the equivalence point for the titration of 0.120 M hydrofluoric acid (HF) with 0.120 M NaOH. The K, of HF is 6.8×104. (Know how to do both acid and base)
General Chemistry - Standalone book (MindTap Course List)
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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.31QP: You are given the following acidbase titration data, where each point on the graph represents the pH...
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Transcribed Image Text:b). What is the conjugate base of NH4?
c) The Ka for NH4* is 5.5x10-10. What is the pKa for its conjugate base? pKa=
d) AlCl3, when dissolved in water, forms a(n) (basic or acidic) solution (Circle one).
Calculate the pH at the equivalence point for the titration of 0.120 M hydrofluoric acid (HF) with
0.120 M NaOH. The K, of HF is 6.8×104. (Know how to do both acid and base)
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