b. E2 R3 Figure 1: 1. In figure 1 Kirchhoff's rules read: -12 R2 - €1 + IR1 - €2 = 0 (a) : €2 - I1 R1 - I3 R3 = 0 (True, False) I3 = I1 + 12 R3+e2 R3+e2 R2 R1 R2+R2R3+R3R1 Rj+jR3+e2 R3 RIR2+R2R3+R3R1 €2 R2- R I = (b) : I2 = (True, False) 13 = (c) : Va - Va = -13 R3 = €1 + 12 R2 = I R1 - €2 (True, False) (d) The direction of the current I2 is opposite of what is assumed in the figure (True, False) (e) If e1 = 12V ; €2 = 10V ; RỊ = 0.012; R2 = 1N ; and R3 = .06N , then |I1| = 171.7A ; |I2| = .3A ; and |13| = 171.4A (True, False) (f) For the same numerical values given in part (e) the energy released by the battery, 1, for a time interval of 1.5 second is : Energye = (I1)t = 3090.5J (True, False)

b. E2 R3 Figure 1: 1. In figure 1 Kirchhoff's rules read: -12 R2 - €1 + IR1 - €2 = 0 (a) : €2 - I1 R1 - I3 R3 = 0 (True, False) I3 = I1 + 12 R3+e2 R3+e2 R2 R1 R2+R2R3+R3R1 Rj+jR3+e2 R3 RIR2+R2R3+R3R1 €2 R2- R I = (b) : I2 = (True, False) 13 = (c) : Va - Va = -13 R3 = €1 + 12 R2 = I R1 - €2 (True, False) (d) The direction of the current I2 is opposite of what is assumed in the figure (True, False) (e) If e1 = 12V ; €2 = 10V ; RỊ = 0.012; R2 = 1N ; and R3 = .06N , then |I1| = 171.7A ; |I2| = .3A ; and |13| = 171.4A (True, False) (f) For the same numerical values given in part (e) the energy released by the battery, 1, for a time interval of 1.5 second is : Energye = (I1)t = 3090.5J (True, False)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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