b) Uniform streams of fluid cross the boundary of a control volume containing a solid object. Briefly explain how Newton's 2nd and 3rd laws allow the resultant force vector acting on the body to be derived. Figure 2 shows a steady, uniform two-dimensional jet of liquid in the atmosphere impinging on a flat plate inclined at an angle q to the jet axis. The jet cross section area is A, and its velocity is u. The liquid density isr. It is assumed that there are no flow losses, and that all the streamlines end up parallel to the plate. Explain why the resultant force acts perpendicular to the plate, and show that its magnitude is: R22. A.u cosz Figure 2

b) Uniform streams of fluid cross the boundary of a control volume containing a solid object. Briefly explain how Newton's 2nd and 3rd laws allow the resultant force vector acting on the body to be derived. Figure 2 shows a steady, uniform two-dimensional jet of liquid in the atmosphere impinging on a flat plate inclined at an angle q to the jet axis. The jet cross section area is A, and its velocity is u. The liquid density isr. It is assumed that there are no flow losses, and that all the streamlines end up parallel to the plate. Explain why the resultant force acts perpendicular to the plate, and show that its magnitude is: R22. A.u cosz Figure 2

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q4/ The solid shown consists of a cone of radius (r) and height (h₁) and a cylinder of radius (r) and height (h₂), the dimensions at any time (t) are given by: r = 2 + t h₁ = 3t²-t, h₂= t³ - (1²/2) S Using the Chain Rule for partial derivatives to find the rate of changing in volume of the solid (V) at (t = 1) Ans./ 40T hl h2
2. The acceleration of a body is a = 5v. Att = 0, s = 0, and vo = 2 m/s. a. Find v(t). b. Find v(s).
Subject - Solid mechanics
Section 4.3 and 4.4 Control Volume and System Representations and the Reynolds Transport Theorem 4.32 Water flows through a duct of square cross section as shown in Fig. P4.32 with a constant, uniform velocity of V = 20 m/s. Consider fluid particles that lie along line A-B at time t = 0. De- termine the position of these particles, denoted by line A'-B', when t = 0.20 s. Use the volume of fluid in the region between lines A-B and A'-B' to determine the flowrate in the duct. Re- peat the problem for fluid particles originally along line C-D and along line E-F. Compare your three answers. V - 20 m/s B B' A A' C C FIGURE P4.32 D 45° E 0.5 m
calculate the value of the force exerted by the water above the window of the dam. Be sure to explain why if the pressure varies from the surface of the water, the lower limit for the integral is taken from depth "a" and not from zero? (it is convenient that you make diagrams to support your answer).
SUBJECT: Statics of rigid bodies. I need answer asap
The direction of the force of 2 points static friction between any two surfaces in contact with each other is opposite to the direction of relative motion. True False O Not true for the static friction Can't be decided on the provided data Static friction can be 3 points calculated at which state of the body; * When a body is at the verge of motion When a body is in motion When a body is sliding None of these
2. Three particles are situated in 3-D space. The position of each particle is represented by the following vectors: • A 5-kg particle at 7 = 4î + 3j + 5k • A 3-kg particle at = -3î + 5j + 3k A 6-kg particle at F = 5î – 6k A. Find the location of the center of mass of these particles. B. How far is each particle from the center of mass?
Determine reaction forces using principle of minimum potential energy given in the image. Note:hand written solution not allowed.
Please solve it