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- You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.A 22-k resistor and a 0.02-F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V Select one: a. 0.501 ms b. 0.66 ms c. 0.44 ms d. 0.70 ms
- Capacitors of 4 µF and 8 μF are connected in parallel. And a capacitor of 24 µF is connected in series with it, then full capacitance, total charge and when 32 volts is supplied. Then find the charge on each capacitor. 4μF 8μF V₁ 32V 244F V21. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.The two parallel plate capacitors (C1 and C2) are initially charged by an external power source and the power source is disconnected later, leaving the two capacitors charged as seen in the figure. The capacitor C1 has dielectric material between its parallel plates. The length of the two parallel plate capacitors are the same. The distance between the parallel plates of the capacitors are also the same. However the width of C1 is 2a whereas the width of C2 is a. The amount of charge stored in C1 is Q1 = 10q. It is also observed that the amount of charge stored in C2 becomes Q2 = 4q if the dielectric material in C1 is removed (and replaced by air). What is the dielectric constant of the dielectric material that is used in C1?
- A capacitor of capacity C₁ is charged upto V volt and then connected in parallel to an uncharged capacitor of capacity C₂. The final potential difference across each will be (a) (c) C₂V G₁ + C₂ (1+2) GV G + C₂ (4) (1-²) v (b)An inductor of 230 milli Henry, a capacitor of 15 micro farad and a 200 ohm resistor are in series across a 36 V and 60 Hz voltage source. Find the total current a. 150 mA b. 0.164 A c. 0.2 A d. 170 mAUsing the series circuit in Figure 3 consisting of a voltage source V, the resistor R and the fully uncharged capacitor C, how to find the value of the capacitance C considering as known data the time constant of the circuit T and the value of the resistor R? V ww R
- The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to 1/20 of its initial voltage? Take R₁ = 2.00 Q, R₂=4.00 Q, R3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.) E R₂ R₂ BAFor R1=9000, R2=2000, R3=6000, R4=5000, C1=0.006, C2=D0.002 & 11=0.007 A in the shown circuit, obtain the energy stored in each capacitor under dc conditions. C2 R4 ŽR3 ER2 ŽRI C1= Energy stored in C1= Energy stored in C2=In the figure ɛ = 10.0 V, R1 = 4.00 N, and R2 = 1.00 N. The inductor is ideal. If the switch is closed for a long time, what is the current through the inductor. Give your answer in A. Şekildeki devrede ɛ = 10.0 V, R1 = 4.00 N , ve R2 = 1.00 N olarak verilmişlerdir. Solenoidin iç direnci yoktur. Anahtar kapatıldıktan çok uzun süre sonra solenoidden geçen akım A cinsinden nedir. R1 R2 L E Yanıtınız