b) It will be wider c) It will not change Construct the requested confidence interval. -13. An article estimates, with 90% confidence, that the proportion of elementary school teachers who are female is 82%. The article also states the maximum error of their estimate is 3%. Determine the resulting 90% confidence interval for the proportion of elementary school teachers who are female. a) (82%, 85%) b)(79%, 82%) c) (80.5%, 83.5%) d)(87%, 93%) e) (79%, 85%) Construct the requested confidence interval. In a random sample of 60 computers, the mean repair cost was $150 with a standard deviation of $36. Construct a 90% confidence interval for the population mean. 14.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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b) It will be wider
c) It will not change
Construct the requested confidence interval.
-13. An article estimates, with 90% confidence, that the proportion of elementary school teachers who are
female is 82%. The article also states the maximum error of their estimate is 3%.
Determine the resulting 90% confidence interval for the proportion of elementary school teachers
who are female.
a) (82%, 85%)
b)(79%, 82%)
c) (80.5%, 83.5%)
d)(87%, 93%)
e) (79%, 85%)
Construct the requested confidence interval.
In a random sample of 60 computers, the mean repair cost was $150 with a standard deviation of $36.
Construct a 90% confidence interval for the population mean.
14.
Transcribed Image Text:b) It will be wider c) It will not change Construct the requested confidence interval. -13. An article estimates, with 90% confidence, that the proportion of elementary school teachers who are female is 82%. The article also states the maximum error of their estimate is 3%. Determine the resulting 90% confidence interval for the proportion of elementary school teachers who are female. a) (82%, 85%) b)(79%, 82%) c) (80.5%, 83.5%) d)(87%, 93%) e) (79%, 85%) Construct the requested confidence interval. In a random sample of 60 computers, the mean repair cost was $150 with a standard deviation of $36. Construct a 90% confidence interval for the population mean. 14.
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