B In Figure 6, column BD has a square cross section. It is pinned at B and fixed against rotation at D. However, there is no restraint on the horizontal 10 in. 40 in.- displacement of point D. Derive a symbolic formula for the critical load of colunmn BD, as a function of E (the Young's modulus of the material that makes column BD), I (the moment of inertia of the cross section of BD) and L (the length of column BD). 45 in. 35 in. 0.625 in. 0.625 in. D

A hollow steel [E = 30,000 ksi] tube (1) with an outside diameter of 3.50 in. and a wall thickness of 0.219 in. is fastened to a solid 2.00-in.-diameter aluminum [E = 10,000 ksi] rod. The assembly is attached to unyielding supports at the left and right ends and is loaded as shown. Assume P=18 kips, Q=10 kips, L1=6 ft, L2=7 ft, and L3=7 ft.  (A) Calculate the cross-sectional area of steel tube (1), A1, and the cross-sectional area of the aluminum rods (2) and (3). in inches squared (B) Find the force in the steel tube (1), F1, and the forces F2 and F3, which are the forces in the aluminum rods.  Use the correct sign for each force.  By convention, a tension force is positive, and a compression force is negative. IN kips (C) Find σ1, σ2, and σ3, the normal stresses in members (1), (2), and (3), respectively. By convention, a tension stress is positive, and a compression stress is negative. IN KSI (D) Determine δ1 and δ2, the deformations of members (1) and (2), respectively.  By…

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Please show work for part B of the question shown below. Thank you!!