**Question (b): How much work would have to be done to bring a 980-kg automobile traveling at 72 km/h to a stop?**Explanation:This question involves calculating the work required to stop an automobile. The work done on an object is related to the change in its kinetic energy. The kinetic energy (KE) of an object is given by the equation:\[ KE = \frac{1}{2}mv^2 \]where \( m \) is the mass of the object (980 kg) and \( v \) is its velocity (72 km/h). To find the work done, you need to convert the velocity from kilometers per hour to meters per second, use the kinetic energy formula, and determine the change in kinetic energy (from its initial value to zero, since the automobile stops).

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Description: **Question (b): How much work would have to be done to bring a 980-kg automobile traveling at 72 km/h to a stop?**Explanation:This question involves calculating the work required to stop an automobile. The work done on an object is related to the ch

Given data: Mass (m) = 980 kg Initial velocity (u) = 72 km/h Final velocity (v) = 0 Required: The…

Answered: (b) How much work would have to be done…

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(b) How much work would have to be done to bring a 980-kg automobile traveling at 72 km/h to a stop? J

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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