pls help me solve part b thank you A 0.320 kg puck at rest on a horizontal frictionless surface is struck by a 0.220 kg puck moving in the positive x directionwith a speed of 4.03 m/s. After the collision, the 0.220 kg puck has a speed of 1.28 m/s at an angle of 8 = 60.0⁰counterclockwise from the positive x axis.(a) Determine the velocity of the 0.320 kg puck after the collision. Express your answer in vector form.2.330 -0.762m/s=(b) Find the percent of kinetic energy lost in the collision.AK100= 53.821XSince we know the mass of each puck, if we can determine the speed of each puck both before and after thecollision, we can determine the kinetic energy of each puck before and after the collision and then the percent ofthe initial kinetic energy lost.%

m1=0.320 kgu1=0 (initial velocity of m1)v1=2.332+0.7622=2.45 m/s (final velocity of m1)m2=0.220…

Answered: (b) Find the percent of kinetic energy…

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(b) Find the percent of kinetic energy lost in the collision. AK 100 = 53.821 X K₁

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

pls help me solve part b thank you

A 0.320 kg puck at rest on a horizontal frictionless surface is struck by a 0.220 kg puck moving in the positive x direction
with a speed of 4.03 m/s. After the collision, the 0.220 kg puck has a speed of 1.28 m/s at an angle of 8 = 60.0⁰
counterclockwise from the positive x axis.
(a) Determine the velocity of the 0.320 kg puck after the collision. Express your answer in vector form.
2.330 -0.762
m/s
=
(b) Find the percent of kinetic energy lost in the collision.
AK
100
= 53.821
X
Since we know the mass of each puck, if we can determine the speed of each puck both before and after the
collision, we can determine the kinetic energy of each puck before and after the collision and then the percent of
the initial kinetic energy lost.%

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