part b estion FourExplain why the average density of metals is higher than that of ceramics or polymers i.e pmetals >(a)Peramics > Ppolymers.(b) Copper crystallises as FCC (face centred cubic). Given that the atomic radius and mass of a given coppersample are 1.28 x 10:10 m and 64.15 g respectively, calculate the density of the copper sample. TakeAvogadro's number, NA = 6.023 x 1023 atoms/mole.(c) The linear density, LD, of an atom is given by the equation =Natomswhere Natoms is theLdvnumber of atoms and Lav is the unit length of the direction vector, both taken on a particular plane.Calculate the linear density of an aluminium atom with a lattice parameter of 4.05 x 1010 m and in a[110] direction.(d) Using neat sketches, show the difference between a triclinic and hexagonal crystal systems.

Answered: Image /qna-images/answer/97274c1a-6e9b-4d4e-b978-2fb92bc25b1d.jpg

Answered: (b) Copper crystallises as FCC (face…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Vanadium (V) has a BCC crystal structure. The atomic radius is R = 0.132 nm and the atomic mass is M = 50.94 g/mole. What is the density of Vanadium in g/mm ? Given: Avogadro's Number NA = 0.6023 x 1024 (atoms/mole) Select one: O a, 0.021 O b. 0.011 Oc.1.5 d. 0.0087 e. 0.00597 Potassium (K) has the Body-Centered Cubic (BC) crystal structune. The edge length is a = 0.533 nm. What is the linear density in atoms/nm along direction (01112 Select one: O ENG O O 0 00
Vanadium (V) has a BCC crystal structure. The atomic radius is R = 0.132 nm and the atomic mass is M = 50.94 g/mole. What is the density of Vanadium in g/mm3? Given: Avogadro’s Number NA = 0.6023 × 1024 (atoms/mole) Select one: a. 1.5 b. 0.021 c. 0.011 d. 0.0087 e. 0.00597
Sodium chloride (NaCl) has the rock salt crystal structure and a density of 2.17 g/cm³. The atomic weights of sodium and chlorine are 22.99 g/mol and 35.45 g/mol, respectively. (a) Determine the unit cell edge length. nm (b) Determine the unit cell edge length from the radii in the table below assuming that the Nat and Cl- ions just touch each other along the edges. nm Cation Mg2+ Fe2+ Na+ Ionic Radius (nm) 0.072 0.077 0.102 Anion Ionic Radius (nm) CI- 0²- 0.181 0.140
the answer should be equal to 0.842
O h. 0.74 Silver (Ag) has the FCC crystal structure. The atomic radius is R = 0.144 nm and the atomic mass is M = 107.87 g/mole. What is the density of Silver in g/m? Given: Avogadro's Number NA = 0.6023 x 1024 (atoms/mole) Select one: a. 10.6x106 O b. 10.6×105 O c. 10.6×10 O d. 10.60 O e. 10.6x10 Chromium (Cr) has the Boody-Centered Cubic (BCC) crystal structure. The edge length is a= 0.288 nm. What is the linear density in atoms/nm along direction (111P Select one: 9:12 PM O a. 7.48 O O e 4) A ENG 15-Apr-2021
Vanadium has the Body-Centered Cubic (BCC) crystal structure. The edge length "a" of the unit cell of Vanadium is a 0.3048 nm at room %3D temperature (20°C). Calculate atomic radius "r" of Vanadium? Select one: a. 0.488 b. 0.428 c. 0.304 d. 0.612 e. 0,132
Tungsten (W) has the BCC crystal structure. The atomic radius is R = 0.137 nm and the atomic mass is M = 183.95 g/mole. %3D What is the density of Tungsten in g/cm³? Given: Avogadro's Number NA = 0.6023 × 1024 (atoms/mole) Select one: O a. 5.30 O b. 6.28 Oc. 2.534 Od. 6.77 Oe. 19.28
i need the answer quickly
Iron has a BCC crystal structure, an atomic radius of 0.124 nm, and an atomic weight of 55.85 g/mol. Compute its theoretical density and compare with its experimental density, which is 7.87 g/cm3. Which one is higher? O Experimental density is higher. O Not enough information to compute the theoretical density. O Theoretical density is higher. O Neither. Both are equal.
Hi, I have a materials engineering question.
Compute the density of Zinc, where the atomic radius of Zn=1.453×10-8 and atomic weight =72.4 g/mol and the crystal structure is BCC?
O f.0.47 g. 0.59 Oh.0.41 Clear my choice Silver (Ag) has the FCC crystal structure. The atomic radius is R = 0.144 nm and the atomic mass is M = 107.87 g/mole. What is the density of Silver in g/m7 Given: Avogadro's Number NA = 0.6023 x 10 (atoms/mole) Select one: Ca 10.6x10 o10.6x10 Cc.10.6-10 Gd.10.6x10 Oe 1060 Calcium (Ca) hashe Face-Certered Cubic (FCC) crystal strucure.The edge length is a = 0.548 nm. What is the linear density in atoms/nm along direction [100]?

SEE MORE QUESTIONS

Recommended textbooks for you

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Elements Of Electromagnetics

Mechanical Engineering

ISBN:

9780190698614

Author:

Sadiku, Matthew N. O.

Publisher:

Oxford University Press

Mechanics of Materials (10th Edition)

Mechanical Engineering

ISBN:

9780134319650

Author:

Russell C. Hibbeler

Publisher:

PEARSON

Thermodynamics: An Engineering Approach

Mechanical Engineering

ISBN:

9781259822674

Author:

Yunus A. Cengel Dr., Michael A. Boles

Publisher:

McGraw-Hill Education

Control Systems Engineering

Mechanical Engineering

ISBN:

9781118170519

Author:

Norman S. Nise

Publisher:

WILEY

Mechanics of Materials (MindTap Course List)

Mechanical Engineering

ISBN:

9781337093347

Author:

Barry J. Goodno, James M. Gere

Publisher:

Cengage Learning

Engineering Mechanics: Statics

Mechanical Engineering

ISBN:

9781118807330

Author:

James L. Meriam, L. G. Kraige, J. N. Bolton

Publisher:

WILEY

SEE MORE TEXTBOOKS

(b) Copper crystallises as FCC (face centred cubic). Given that the atomic radius and mass of a given copper sample are 1.28 x 1010 m and 64.15 g respectively, calculate the density of the copper sample. Take Avogadro's number, NA = 6.023 x 10²3 atoms/mole.