[B] A loan of $210000 is repaid over 20 years by monthly payments of $1575. Use two iterations of the Newton-Raphson method starting with the initial guess of an annual interest rate of 12% (compounded monthly), to determine the annual interest rate. NOTE: IfP is borrowed at a rate of r per period, and is repaid over N periods by payments of Y, then: Pr + Y[(1+r)-N – 1] = 0 If f(r) = 210000r + 1575[(1+r) 400 – 1] and f'(r) = k – a(1+ br) €, then: k =

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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[B] A loan of $210000 is repaid over 20 years by monthly payments of $1575. Use two iterations of the
Newton-Raphson method starting with the initial guess of an annual interest rate of 12% (compounded
monthly), to determine the annual interest rate.
NOTE: IfP is borrowed at a rate of r per period, and is repaid over N periods by payments of Y, then:
Pr + Y[(1+r)-N – 1] = 0
If f(r) = 210000r + 1575[(1+r) 400 – 1] and f'(r) = k – a(1+ br)-€, then:
k
b =
c =
annual interest rate
||
Transcribed Image Text:[B] A loan of $210000 is repaid over 20 years by monthly payments of $1575. Use two iterations of the Newton-Raphson method starting with the initial guess of an annual interest rate of 12% (compounded monthly), to determine the annual interest rate. NOTE: IfP is borrowed at a rate of r per period, and is repaid over N periods by payments of Y, then: Pr + Y[(1+r)-N – 1] = 0 If f(r) = 210000r + 1575[(1+r) 400 – 1] and f'(r) = k – a(1+ br)-€, then: k b = c = annual interest rate ||
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