b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 + j0 p.u, and the impedance of the electric arc is neglected (Zf = 0 + j0 p.u.). The positive, negative and zero sequence impedance parameters of the generator, transmission lines and transformer are given in Figure Q3.   (i) Determine the positive sequence fault current for the case when a three-phase-to-ground fault occurs at bus 4 of the network   (ii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus 4. Recall that phasors can be expressed in terms of their symmetrical components as shown in the picture attached. where F stands for any three-phase quantity (e.g., current, voltage)   (iii) Determine the short-circuit fault current for the case when a phase-to-phase fault occurs at bus 4

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b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 + j0 p.u, and the impedance of the electric arc is neglected (Zf = 0 + j0 p.u.). The positive, negative and zero
sequence impedance parameters of the generator, transmission lines and transformer are given in Figure Q3.
 
(i) Determine the positive sequence fault current for the case when a three-phase-to-ground fault occurs at bus 4 of the network
 
(ii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus 4. Recall that phasors can be expressed in terms of their symmetrical components as shown in the picture attached. where F stands for any three-phase quantity (e.g., current, voltage)
 
(iii) Determine the short-circuit fault current for the case when a phase-to-phase fault occurs at bus 4
 
 
 
 
 
ReplyForward
V₁ = 120° p.u.
jXan)= j0.1 p.u.
jX(2) j0.15 p.u.
jXdo) = j0.2 p.u.
=
V₂=
= 120° p.u.
V3= 120° p.u. V₁ = 120° p.u.
jX1(1) = j0.15 p.u.
jX2(1) = j0.2 p.u.
1 jx(2) j0.15 p.u. 2 A 3 X2(2) 10.2 p.u. 4
jX11(0) = j0.2 p.u.
jX(2(0) = j0.25 p.u.
jXT(1) = j0.15 p.u.
jXT(2) = j0.15 p.u.
jXT(0) = j0.15 p.u.
Figure Q3. Circuit for problem 3b).
0
Transcribed Image Text:V₁ = 120° p.u. jXan)= j0.1 p.u. jX(2) j0.15 p.u. jXdo) = j0.2 p.u. = V₂= = 120° p.u. V3= 120° p.u. V₁ = 120° p.u. jX1(1) = j0.15 p.u. jX2(1) = j0.2 p.u. 1 jx(2) j0.15 p.u. 2 A 3 X2(2) 10.2 p.u. 4 jX11(0) = j0.2 p.u. jX(2(0) = j0.25 p.u. jXT(1) = j0.15 p.u. jXT(2) = j0.15 p.u. jXT(0) = j0.15 p.u. Figure Q3. Circuit for problem 3b). 0
1-6
Fa [1 1
1
Fb
=
a²
a
C
Fao
1
a
a² F
Fal
a1
a2-
Transcribed Image Text:1-6 Fa [1 1 1 Fb = a² a C Fao 1 a a² F Fal a1 a2-
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