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Step 1
Please explain how you can confirm 1.25mg of heavy metals are consumed per day? It seems to me that this is only true once the contamination of the tank reaches 0.00125m/L.
My thinking is this:
Assume the tank begins with a heavy metal concentration lower than 1.25mg/L.
Introducing 1kL of water with concentration 1.25mg/kL to a 7.5kL supply results in:
8.5kL of water, and 1.25mg of heavy metals
Therefore the supply's concentration = 1.25mg/8.5kL
And removing 1kL results in the tank having the same concentration (1.25mg/8.5kL). The question expects you to assume the tank is well mixed.
Also, I acknowledge that this thinking assumes that the contaminated water is all added before any water is removed, which is an incorrect assumption, but it just demonstrates where my confusion is.
Step 1
Please explain how you can confirm 1.25mg of heavy metals are consumed per day? It seems to me that this is only true once the contamination of the tank reaches 0.00125m/L.
My thinking is this:
Assume the tank begins with a heavy metal concentration lower than 1.25mg/L.
Introducing 1kL of water with concentration 1.25mg/kL to a 7.5kL supply results in:
8.5kL of water, and 1.25mg of heavy metals
Therefore the supply's concentration = 1.25mg/8.5kL
And removing 1kL results in the tank having the same concentration (1.25mg/8.5kL). The question expects you to assume the tank is well mixed.
Also, I acknowledge that this thinking assumes that the contaminated water is all added before any water is removed, which is an incorrect assumption, but it just demonstrates where my confusion is.
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