B = {3 – 3x, 9 – 2x – 9x², 13 – 4x – 12x?} is a basis for P2. The coordinate vector of p(x) = 4 + 2x – 6x² relative to the basis B is [p]B =

Find the coordinate vector [x] of x relative to the given basis B = {b₁, D₂, D3}. b₁ = 1 -1 -4 b₂ = [x] = (Simplify your answer.) -2 3, b₂ = 8 2 -2 6 X = 5 -4 22

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Find the coordinate vector [x]R of the vector x relative to the given basis B. 5 - 25 b = 5 , b2 = - 3 X = - 1 and B = %3D - 4 - 3 17 O A. - 2 - 3 О В. - 250 - 2 - 119 О с. - 130 – 122 103 O D. - 2 – 4

Find the coordinate vector [x]; of x relative to the given basis B= (b1,b2}. 13 -3 X = - 5 b1 b2 -2 - 1 [x]s

Find the vector x determined by the given coordinate vector [x]B and the given basis B. = { [2] [i]} , [×] B = B [3]

Find the angle a between the vectors απ -4 4 and 1 6

Given x₁ = [¹¹]¹, x₂ = [1 -1 1]], *₂ = [1 [1 basis vectors. Assume that {xi} form. The a 121,3 0 0]] Find reciprocal basic vectors. Express the vector Y = {6 3 1] in terms of these basis vectors.