Ax + B Cx+D Then (22 + 3)2 8.5.57 (2² +3)2 x2 +3 2 + 5z = (Az + B)(x² + 3) + Cz + D = Ar + Bx² + (3.A + C)r +3B+ D. Then A = 1, B = 0, 3A+ C = 5, and 3B+ D = 0. So C= 2 and D=0. We have + 5x 2.r In a° + 3| - (x² + 3)² dr = (22 +3)2 dx = +C. r2 2+3 +3
Ax + B Cx+D Then (22 + 3)2 8.5.57 (2² +3)2 x2 +3 2 + 5z = (Az + B)(x² + 3) + Cz + D = Ar + Bx² + (3.A + C)r +3B+ D. Then A = 1, B = 0, 3A+ C = 5, and 3B+ D = 0. So C= 2 and D=0. We have + 5x 2.r In a° + 3| - (x² + 3)² dr = (22 +3)2 dx = +C. r2 2+3 +3
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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