avg An ion's position vector is initially = 7.01 - 7.0+ 9.0k, and 5.0 s later it is = 5.01 + 6.0 - 5.0k, all in meters. What was its v during the 5.0 s? (Express your answer in vector form.)

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Chapter1: Units, Trigonometry. And Vectors
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An ion's position vector is initially = 7.01 - 7.01 + 9.0k, and 5.0 s later it is = 5.01 + 6.0 - 5.0k, all in meters. What was its
the 5.0 s? (Express your answer in vector form.)
V
avg
Additional Materials
m/s
Algebra-Squareroots & Squares
avg
during
Transcribed Image Text:→ An ion's position vector is initially = 7.01 - 7.01 + 9.0k, and 5.0 s later it is = 5.01 + 6.0 - 5.0k, all in meters. What was its the 5.0 s? (Express your answer in vector form.) V avg Additional Materials m/s Algebra-Squareroots & Squares avg during
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Step 1 GIVEN
Initial,7=7.01 - 7.0ĵ+ 9.0k
Final, 7=5.01 +6.0ĵ- 5.0k
Time, t = 5 s
Step 2 SOLUTION
Velocity vector can be given as,
Vaug =
اساة
Vavg
=
(5.01 + 6.0ĵ
5.0k)
Transcribed Image Text:→ Step 1 GIVEN Initial,7=7.01 - 7.0ĵ+ 9.0k Final, 7=5.01 +6.0ĵ- 5.0k Time, t = 5 s Step 2 SOLUTION Velocity vector can be given as, Vaug = اساة Vavg = (5.01 + 6.0ĵ 5.0k)
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