At time t = 0, an electron with kinetic energy 18 keV moves through x = 0 in the positive direction of an x-axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has a magnitude of 58.8 µT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x-axis in centimeters when the electron reaches coordinate x = 29 cm?

At time t = 0, an electron with kinetic energy 18 keV moves through x = 0 in the positive direction of an x-axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has a magnitude of 58.8 µT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x-axis in centimeters when the electron reaches coordinate x = 29 cm?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter26: Electromagnetism

Section: Chapter Questions

Problem 1STP

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