At the start of the compression process in the reciprocating compressor of refrigeration plant the refrigerant is at 1.5 bar, dry saturated. At the end of the compression process, which is according to a reversible polytropic law pv-C., The pressure is 6.5 bar. Using the properties of refrigerant given as table, interpolating where necessary, calculate. • The change of specific entropy during the •

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3) A cup of rather dilute hot tea initially at 140 degrees F is served to a customer at Howard Johnson's. Unfortunately, before they get around to drinking it, it has spontaneously cooled off to 200 0 100 degrees F. Calculate the change in this process. The temperature of the entropy of the universe for restaurant (the surroundings) is 70 degrees F. (DHD 2/6/22) Suppose that the heat has problem 3, in order to save the inside temperature is been turned off in the HoJo's in money in the cold winter months, and 32 degrees F. The hot tea cools from HOWARD 140 degrees F to 32 degrees F, and then freezes, making it JOHNSON'S impossible to drink. What is the change in entropy of the universe in this case? (DHD 2/6/22) LCE CREAM 28 FLAVORS Restaurant Return to problem 3. Suppose that our customer complains about the cold tea and is given a second cup of hot tea. Feeling especially hungry (for tea?) they mix the hot tea and the cold tea together so that they will have twice as much tea (albeit…

3. Air enters a steady flow compressor at 100 kPa, 27EC and exits at 800 kPa. The process is polytropic with n = 1.3. Determine the specific work and the heat transfer in kJ/kg. Note that this is NOTan adiabatic compressor.