At the instant the displacement of a 2.00 kg object relative the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is V = - (3.97 m/s) i + (2.00 m/s)j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b) and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j and k the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the force acting on the object. components respectively), (a) Number Units m/s^2 (b) Number Units [m/s^2 em (c) Number Unitsm/s^2 em em (d) Number Units Tkg-m^2/s lem (e) Number Units [kg-m^2/s v alem plem (f) Number T Units kg-m^2/s blem (g) Number UnitsN-m blem (h) Number UnitsN-m

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 23PQ: The x and y coordinates of a 4.00-kg particle moving in the xy plane under the influence of a net...
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(d) (e) (f) please Thank you
At the instant the displacement of a 2.00 kg object relative
the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is
V = - (3.97 m/s) i + (2.00 m/s)j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b)
and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j and k
the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the
force acting on the object.
components respectively),
(a) Number
Unitsm/s^2
(b) Number
Units
[m/s^2
em
(c) Number
Unitsm/s^2
em
em
(d) Number
Units
kg-m^2/s
lem
(e) Number
Units
[kg-m^2/s v
alem
plem
(f) Number T
UnitšTkg-m^2/s
blem
(g) Number
UnitsTN-m
blem
(h) Number
UnitsN-m
Transcribed Image Text:At the instant the displacement of a 2.00 kg object relative the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k, its velocity is V = - (3.97 m/s) i + (2.00 m/s)j + (1.05 m/s) k and it is subject to a force F = (5.24 N) i - (3.84 N) j + (9.83 N) k. Find the acceleration of the object ((a), (b) and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i, j and k the torque about the origin acting on the object ((g), (h) and (i) for i, j and k components respectively), and (j) the angle between the velocity of the object and the force acting on the object. components respectively), (a) Number Unitsm/s^2 (b) Number Units [m/s^2 em (c) Number Unitsm/s^2 em em (d) Number Units kg-m^2/s lem (e) Number Units [kg-m^2/s v alem plem (f) Number T UnitšTkg-m^2/s blem (g) Number UnitsTN-m blem (h) Number UnitsN-m
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