At the instant shown, the spring is undeformed. Determine the change in potential energy if the 20 kg disk (kG = 0.5 m) rolls 2 revolutions without slipping.         ½(200)(1.2 π )2 + (20) (9.81) (1.2 π sin 30°)     - ½(200)(1.2 π )2  - (20) (9.81) (1.2 π sin 30°)     ½(200)(1.2 π )2  - (20) (9.81) (1.2 π sin 30°)     ½(200)(1.2 π )2

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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  1. At the instant shown, the spring is undeformed. Determine the change in potential energy if the 20 kg disk (kG = 0.5 m) rolls 2 revolutions without slipping.




     
     

       

    ½(200)(1.2 π )2 + (20) (9.81) (1.2 π sin 30°)

       

    - ½(200)(1.2 π )2  - (20) (9.81) (1.2 π sin 30°)

       

    ½(200)(1.2 π )2  - (20) (9.81) (1.2 π sin 30°)

       

    ½(200)(1.2 π )2

At the instant shown, the spring is undeformed. Determine the change in potential energy if
the 20 kg disk (KG = 0.5 m) rolls 2 revolutions without slipping.
datum
k = 200 N/m
0.3 m
30°
(200) (1.2 TT)² + (20) (9.81) (1.2 π sin 30°)
O-(200)(1.2 TT)² - (20) (9.81) (1.2 T sin 30")
Ⓒ%(200) (1.2 TT)² - (20) (9.81) (1.2 T sin 30°)
O ¹/4(200)(1.2 TT)²
Transcribed Image Text:At the instant shown, the spring is undeformed. Determine the change in potential energy if the 20 kg disk (KG = 0.5 m) rolls 2 revolutions without slipping. datum k = 200 N/m 0.3 m 30° (200) (1.2 TT)² + (20) (9.81) (1.2 π sin 30°) O-(200)(1.2 TT)² - (20) (9.81) (1.2 T sin 30") Ⓒ%(200) (1.2 TT)² - (20) (9.81) (1.2 T sin 30°) O ¹/4(200)(1.2 TT)²
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