At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is about 110 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron in this environment, assuming that the electron has an instantaneous velocity of 4.50 x 106 m/s directed to the east. gravitational force N directed N directed N directed electric force magnetic force downward ♥ upward downward ŵ

A laboratory electromagnet produces a magnetic field of magnitude 1.56 T. A proton moves through this field with a speed of 6.54 ✕ 106 m/s. (a) Find the magnitude of the maximum magnetic force that could be exerted on the proton. N(b) What is the magnitude of the maximum acceleration of the proton? m/s2(c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? (Assume that the electron is moving in the same direction as the proton.) YesNo     Explain. This answer has not been graded yet. (d) Would the electron undergo the same acceleration? YesNo     Explain.

A current-carrying wire is in a B-field and experiences a magnetic force (FB>0). The magnetic force vector is shown below. Choose all the arrows that could represent the current direction. Magnetic force Current direction 45° 45° 45* 45° 45° 40 45° 45°

A proton travels with a speed of 4.90 x 106 m/s at an angle of 62° with the direction of a magnetic field of magnitude 0.240 T in the positive x-direction. (a) What is the magnitude of the magnetic force on the proton? N (b) What is the proton's acceleration? m/s²

A charged particle moving through a magnetic field at right angles to the field with a speed of 30.7 m/s experiences a magnetic force of 2.98 x 10-4 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 4.84 m/s at an angle of 32.2° relative to the magnetic field.

When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle.  Accordingly, the charge begins to move in a circular path.  Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010).  A schematic of such motion is shown below.  The "X"s represent the magnetic field that is directed into the plane of this screen.  The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below.   If a charge of magnitude 7.45x10-17C, with speed 4.66x106 m/s, and mass 7.12x10-25kg moves within the magnetic field of magnitude 3.96x10-2T, what is the resulting radius of the path…

A particle that has an 8.6-μC charge moves with a velocity of magnitude 4.8 × 105 m/s along the +x axis. The maximum possible magnetic force that the charge with the given speed could experience has a magnitude of 0.577 N. Find the magnitude of the magnetic field