At the 95% level, test the hypothesis that the three samples A, B and C are drawn from the same population? BLOCKS A 50 37 47 1 23 4 5 63 44 Select one: SAMPLES B 23 4 25 4 33 a. TS= 7.60 CV = 5.991 b. TS= 6.80 CV = 5.991 c. TS 7.00 CV = 5.991 Od. TS= 6.40 CV = 5.991 C 38 87 53 49 96
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- Being overweight or obese may increases your risk of developing high blood pressure. The weight and systolic blood pressure of 13 randomly selected males in the age group 25 to 30 are shown in the table below. Subject Weight (lb) Systolic BP (mmHg) 1 164 130 2 167 133 3 180 146 4 155 128 5 210 151 6 175 146 7 190 150 8 202 140 9 200 148 10 149 125 11 158 133 12 169 135 13 170 143 Decide which variable should be the response variable (y) and which should be the explanatory variable (x). Describe the relationship. You may draw the scatter plot if you like, but it is not required. What is the correlation of coefficient? What can you tell from the correlation of coefficient?Complete the following table that lists all possible samples of n = 2 scores from the population. Use the first three rows (Samples a-c) as examples. Sample a b с d e f 9 h i Score 1 Score 2 1 Mean of 1 1 SS n-1 4 4 4 7 7 7 Mean of M column= column= 1 SS Mean of column = n 4 7 1 4 7 1 4 7 M = This EX n 1.00 2.50 This 4.00 2.50 4.00 5.50 4.00 5.50 7.00 This SS 0.00 Calculate the mean for all values in the M column, SS column and in column. Which values match the parameters of the population? Identify those statistics that were biased. Identify those statistics that were unbiased. n-1 4.50 18.00 SS n-1 0.00 4.50 18.00 SS 0.00 2.25 9.00 the mean u of the population. The sample mean is ▼ the variance o² of the population. Sis the variance 02 of the population. SS is n-1 estimate of u. estimate of 02. estimate of g².For the following data 4,4,6, 10 o = 2.4 Then C.V.= Select one: O a. 25% O b. 47% Ос. 22.4% d. 40%
- In an investigation of the visual scanning behaviour of deaf children, measurements of eye movement rates were taken on nine deaf and nine normal children as shown in the table below Deaf Children Normal Children 1.81 0.95 2.2 1.49 3.29 1.12 2.13 1.07 2.55 1 2.24 1.85 2.22 1.18 2.89 2.07 2.26 1.18 a. If the two samples are drawn from normal populations, test the hypothesis that on average eye movement rate for normal children is less than deaf children in the population at a 10% level of significance. b. What does the 10% level of significance mean? Does it appear that the distributions of eye-movement rates for deaf children and normal children differ at 5% level of significance (assuming samples are not drawn from normal population)? с.The following data represent petal lengths (in cm) for independent random samples of two species of Iris. Petal length (in cm) of Iris virginica: x1; n1 = 35 5.3 5.7 6.2 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.9 5.1 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.5 1.7 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.6 (a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.) x1 = s1 = x2 = s2 = (b) Let μ1 be the population mean for x1 and let μ2 be the population mean for x2. Find a 99% confidence interval for μ1 − μ2. (Round your answers to two decimal places.) lower limit upper limit (c) Explain what the confidence interval means in the context of this problem. Does the…Which of the following can increase effect size? Select one: O a. increase the distance between means and increase the sample size O b. decrease the variability and increase the distance between means O c. decrease the variability and increase the sample size
- A1The following data represent petal lengths (in cm) for independent random samples of two species of iris. Petal length (in cm) of Iris virginica: x1; n1 = 36 5.2 5.6 6.1 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.8 5.2 5.2 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.6 1.8 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.5 (a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1=s1=x2=s2= (b) Let μ1 be the population mean for x1 and let μ2 be the population mean for x2. Find a 99% confidence interval for μ1 − μ2. (Round your answers to two decimal places.) lower limitupper limit3. Can SAT scores predict college performance? Let x be a variable that represents SAT score of a computer science major, and let y be a variable that represents a student’s GPA upon graduation. A random sample of n =15 computer science majors provided their SAT scores and GPAs: x 1232 1070 1086 1287 1130 1048 1121 1095 1135 1208 1333 1160 1186 1243 1261 y 3.52 2.91 2.4 3.47 3.47 2.37 2.4 2.24 3.02 3.32 3.59 2.54 3.19 3.71 3.58 The scatter diagram for the SAT score and GPA is given below: (a) Find the sample correlation coefficient r. Truncate to two decimal places. What does the value tell you about the data? (b) Find the equation of the least squares line . Truncate to four decimal places. What does the slope mean? (c) Find the value of the coefficient of determination . Truncate to two decimal places. What does this number mean? (d) What is the predicted GPA if a computer science major got a…
- The age of first marriage for women who responded to a survey by the CDC between 2006 and 2010 is used here. The women who first married in their twenties were randomly divided into three groups: A, B, and C. The ANOVA output is supplied below: Count NAS (Missings) 3773 group Count A 1288 B 1246 C 1239 Frequency Source DF 2 group Residual 3770 28 26 24 Response Variable (age) Summary Mean 22 20 T 0 Group Variable Summary NAS Mean (Missings) 23.73787 A 0 23.76941 0 23.77929 0 23.66344 ANOVA Table: age-group Sum of Squares 10.283 26969 Mean Square Std. Dev. Std. Dev. 2.674442 B F Value Pr>F MSG 0.71875 0.48743 MSE Age of First Marriage in 20's 2.728097 2.664101 2.628699 CLet x be the average number of employees in a group health insurance plan, and let y be theaverage administrative cost as a percentage of claims. The following data is based on a randomsample:x 5 7 15 25 35y 40 35 30 20 25a. Plot a scatter diagram of the above data.b. Estimate the sample correlation coefficient r as positive, zero, or negative.c. Interpret your results from parts a. and b.The data to the right are from independent simple random samples from three populations. Determine each of the following. Sample 1 Sample 2 Sample 3 3 3 3 a. SSTR b. MSTR c. SSE d. MSE e. F 4 2 1 8 a. SSTR= (Round to three decimal places as needed.) b. MSTR = (Round to three decimal places as needed.) c. SSE = (Round to three decimal places as needed.) d. MSE = (Round to three decimal places as needed.) e. F = (Round to three decimal places as needed.)