A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
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- The lifespans of lizards in particular zoo are normally distributed. The average lizard lives 3.1 yearsthe standard deviation is 0.6 years. Find the probability that the lizards live longer than 3.1 years or less than 2.5 yearsHint: Draw and label a normal curve and use the percentages of the standard deviations. Write your answer using only numbers and do not include units. For example 95.3% would be entered as 95.3arrow_forwardMean (Average): 76 Population Standard Deviation, σ 19 Total Numbers, N 45 What score represents 2 SDs below the mean?arrow_forwardWhat percent of the total population is found between the mean and the z-score given? (Use the standard normal distribution table and enter your answer to two decimal places.) z = 3.32arrow_forward
- A distribution of values is normal with a mean of 190 and a standard deviation of 4.Find the interval containing the middle-most 30% of scores: Enter your answer using interval notation. Example: (2.1,5.6)arrow_forwardUse the normal distribution of IQ scores, which has a mean of 95 and a standard deviation of 12, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Full data set Standard score % Standard score % −3.0 0.13 0.1 53.98 −2.5 0.62 0.5 69.15 −2 2.28 0.9 81.59 −1.5 6.68 1 84.13 −1 15.87 1.5 93.32 −0.9 18.41 2 97.72 −0.5 30.85 2.5 99.38 −0.1 46.02 3 99.87 0 50.00 3.5 99.98 The percentage of scores between 65 and 113 is __?arrow_forwardThe distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inchesarrow_forward
- Among freshmen at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 100. The SAT score of a student whose score is at the 75th percentile is closest to what value? 665 590 690 620arrow_forwardA distribution of values is normal with a mean of 120 and a standard deviation of 4.Find the interval containing the middle-most 68% of scores: Enter your answer using interval notation. Example: (2.1,5.6)arrow_forwardFind the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 The area of the shaded region is (Round to four decimal places as needed) 96 Garrow_forward
- Find the percent of the total area under the standard normal curve between the following z-scores. z=-0.86 and z=0.86 The percent of the total area between z- -0.86 and z 0.86 is enter your response here %. (Round to the nearest integer.)arrow_forwardUse the table below to find the percentage of data items in a normal distribution that lie a. below and b. above a z-score of negative 1.00 −1.00.arrow_forwardFind the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 120 The area of the shaded region is - (Round to four decimal places as needed.)arrow_forward
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- A First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON
A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:PEARSON