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The class I'm taking is physics for scientists and engineers!

I am completely stuck. Need help. I have attached the problem. Please view both attachments before answering.

*****I need help with parts D , E , F and G please. ******

I have also attached the links to BOTH videos below. If you can please explain your answer so I can fully understand. Thank you so much!

 

Link:  https://youtu.be/eK7dMnnElx8
Link:  https://youtu.be/4IYDb6K5UF8

In this video:
Link e
part A
at around 1:30 she shows an elastic collision of carts with
unequal masses.
Assume the mass of the left cart is 3 kg and the right cart is 1
kg.
If:
• initial velocity of the left cart is 1 m/s
• initial velocity of the right cart is -2 m/s
• final velocity of the left cart is -0.5 m/s
then, what is the velocity of the right cart after it bounces
back? Include the sign to indicate direction.
You should use the formula sum of momentum before equals
sum of momentum after:
momentuminitial = momentumfinal
since momentum = (mass)(velocity) = mv, the sum becomes:
mLVL_initial + MRVR_initial = mL VL_final + MRVR_final
part B
For an elastic collision, the total energy before and after should
be the same. The kinetic energy is:
KE = (1/2)(mass)(velocity)?
What is the total energy before the collision?
To get the total energy before, you need to add the energy of
the left and right cart. In SI units, your answer will be in Joules,
but please report just the numeric part.
part C
What is the total energy after the collision?
Again please use Sl units and report the numeric part.
expand button
Transcribed Image Text:In this video: Link e part A at around 1:30 she shows an elastic collision of carts with unequal masses. Assume the mass of the left cart is 3 kg and the right cart is 1 kg. If: • initial velocity of the left cart is 1 m/s • initial velocity of the right cart is -2 m/s • final velocity of the left cart is -0.5 m/s then, what is the velocity of the right cart after it bounces back? Include the sign to indicate direction. You should use the formula sum of momentum before equals sum of momentum after: momentuminitial = momentumfinal since momentum = (mass)(velocity) = mv, the sum becomes: mLVL_initial + MRVR_initial = mL VL_final + MRVR_final part B For an elastic collision, the total energy before and after should be the same. The kinetic energy is: KE = (1/2)(mass)(velocity)? What is the total energy before the collision? To get the total energy before, you need to add the energy of the left and right cart. In SI units, your answer will be in Joules, but please report just the numeric part. part C What is the total energy after the collision? Again please use Sl units and report the numeric part.
part D
Now, imagine we run the experiment again, this time with
velcro between the carts so that they stick together (like the
velcro from the international space station video).
In this case, both carts stick together and move with the same
speed. The conservation of momentum equation becomes:
MLVL_initial + MRVR_initial = (ml +mr)Vfinal
What is Vfinal?
What is the total initial kinetic energy in the velcro
experiment?
Use:
part E
KE = (1/2)(mass)(velocity)2
What is the total final kinetic energy in the velcro experiment?
Use:
KE = (1/2)(mass)(velocity)?
part F
In both experiments, we say that momentum was conserved,
meaning the total quantity was the same before and after.
Based on your calculations, was energy conserved in the
collisions?
Which ones?
part G
Why do you think this is the case?
expand button
Transcribed Image Text:part D Now, imagine we run the experiment again, this time with velcro between the carts so that they stick together (like the velcro from the international space station video). In this case, both carts stick together and move with the same speed. The conservation of momentum equation becomes: MLVL_initial + MRVR_initial = (ml +mr)Vfinal What is Vfinal? What is the total initial kinetic energy in the velcro experiment? Use: part E KE = (1/2)(mass)(velocity)2 What is the total final kinetic energy in the velcro experiment? Use: KE = (1/2)(mass)(velocity)? part F In both experiments, we say that momentum was conserved, meaning the total quantity was the same before and after. Based on your calculations, was energy conserved in the collisions? Which ones? part G Why do you think this is the case?
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