Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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At a certain temperature, the equilibrium constant K for the following reaction is 0.71:
N₂(g) + O₂(g) 2 NO(g)
Use this information to complete the following table.
Suppose a 46. L reaction vessel is filled with 1.5 mol of N₂ and
1.5 mol of O₂. What can you say about the composition of the
mixture in the vessel at equilibrium?
What is the equilibrium constant for the following reaction?
Round your answer to 2 significant digits.
2 NO(g)
N₂(9)+0₂ (9)
What is the equilibrium constant for the following reaction?
Round your answer to 2 significant digits.
3 N₂(9)+30₂(9)
I Don't Know
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- 6 NO (9)
!
1
Q
A
2
W
S
O There will be very little N₂ and 0₂.
O There will be very little NO.
ONeither of the above is true.
#3
K = 0
K = 0
E
D
$
4
R
olo 5
%
LL
© 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce
F
20
T
X
6
G
S
&
Y
7
H
*
8
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Transcribed Image Text:At a certain temperature, the equilibrium constant K for the following reaction is 0.71: N₂(g) + O₂(g) 2 NO(g) Use this information to complete the following table. Suppose a 46. L reaction vessel is filled with 1.5 mol of N₂ and 1.5 mol of O₂. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 NO(g) N₂(9)+0₂ (9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 3 N₂(9)+30₂(9) I Don't Know tab caps lock Submit esc - 6 NO (9) ! 1 Q A 2 W S O There will be very little N₂ and 0₂. O There will be very little NO. ONeither of the above is true. #3 K = 0 K = 0 E D $ 4 R olo 5 % LL © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce F 20 T X 6 G S & Y 7 H * 8
Expert Solution
Check Mark
Step 1: Introduction to the given data

Given reaction: text N end text subscript 2 text (g) + O end text subscript 2 text (g) ⇌ 2NO(g) end text

The equilibrium constant of the given reaction, text K = 0.71 end text

we have to calculate the equilibrium constants for the reactions:

text  2NO(g)    end text ⇌  text   N end text subscript 2 text (g) + O end text subscript 2 left parenthesis g right parenthesis

text 3N end text subscript 2 text (g) +3 O end text subscript 2 text (g) ⇌ 6NO(g) end text


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