At 250°C an equilibrium mixture of SbCl3(g), Cl2(g), and SbCl5(g) has the partial pressures 0.670 bar, 0.438 bar, and 0.228 bar, respectively. Calculate the new equilibrium pressures if the volume of the reaction vessel is doubled. Answer: PCl2 = 0.258 bar; PSbCl3 = 0.374 bar; PSbCl5 = 0.075 bar

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Q: At 250°C an equilibrium mixture of SbCl3(g), Cl2(g), and SbCl5(g) has the partial pressures 0.670…

A:

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