Assumptions. Alphabet E = {a, b} L = {a"b* : n >0 An mod 3 = 0} To do in this exercise. Find a context-free grammar G such that L(G) = L. Save your context-free grammar as a JFLAP jff file, and submit that jff file to Canvas as your solution to this exercise. %3D

Assumptions. Alphabet E = {a, b} L = {a"b* : n >0 An mod 3 = 0} To do in this exercise. Find a context-free grammar G such that L(G) = L. Save your context-free grammar as a JFLAP jff file, and submit that jff file to Canvas as your solution to this exercise. %3D

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Code in Prolog. Do not use in built libraries. Implement the following relation to get a vector product from two list of numbers. prodVector It should work like the following: ?- prodVector([3, 2, 5], [3, 4, 2], P). P = [9, 8, 10] . ?- prodVector([], [], P). P = [] .
The conjugations for all Spanish regular verbs can be built by using the three forms for verbs ending in -ar, -er and -ir. Create a function that takes a verb as string, and returns a string with the six person/number combinations (like in the examples). Watch out for verbs ending in -ir (check the notes). Try programming the construction rather than forming structures with arrays. Examples espVerb("pasar") → "Yo paso, tú pasas, él pasa, nosotros pasamos, vosotros pasá espVerb ("unir") → "Yo uno, tú unes, él une, nosotros unimos, vosotros unís, ell espVerb ("correr") → "Yo corro, tú corres, él corre, nosotros corremos, vosotros The smallest category of regular Spanish verbs is those that end in -ir. To conjugate them, remove the infinitive ending and then add one of the following verb endings: Singular Plural 1st person yo -o 2nd person tú -es 3rd person él -e *** Notes nosotros -imos vosotros -ís ellos -en • This is for European Spanish, so the second person plural is vosotros pasais,…
Please write Lisp code for the following problem. Consider the list:((name (number1 nation)) (MusicPurchasedNorway) (Pressfreedom Norway) (NobelLiterWinners France)(MovieTixHighPrices Switzerland))write a function to access the MovieTixHighPricesvalue using carand cdr.2 (Your function should work on any property list with this set of properties in this order.)
Please write Lisp code for the following problem. Consider the list:(name (number1 nation)) (MusicPurchasedNorway) (Pressfreedom Norway) (NobelliterWinners France)(MovieTixHighPrices Switzerland))write a function to access the MovieTixHighPricesvalue using carand cdr.? (Your function should work on any property list with this set of properties in this order.)
A- Declare a self-referential structure for a linked list having one data StudentNode field called GPA (float), and one pointer to StudentNode called next. B- Write a non-recursive function - that counts all the GPAS that are less than or equal to 2 in your linked list starting from the head of the list. Example: If the list is 1.9->2->3.5->4->1.8, the function should return 3. C- Write a recursive function that prints all the GPAS that are higher or equal to 3.5 in your linked list starting from the head of the list. Example: If the list is 1.9->2->3.5->4->1.8, the function should print: 3.5->4.
Part 1: autocomplete term. Write an immutable data type Term.java that represents an autocomplete term-a query string and an associated integer weight. You must implement the following API, which supports comparing terms by three different orders: lexicographic order by query string (the natural order); in descending order by weight (an alternate order); and lexicographic order by query string but using only the first r characters (a family of alternate orderings). The last order may seem a bit odd, but you will use it in Part 3 to find all query strings that start with a given prefix (of length r). public class Term implements Comparable { // Initializes a term with the given query string and weight. public Term (String query, long weight) // Compares the two terms in descending order by weight. public static Comparator byReverseWeight0rder () // Compares the two terms in lexicographic order, // but using only the first r characters of each query. public static Comparator…
Rewrite the set of productions below in Extended Backus-Naur Form (EBNF). Set of Productions: P01: FN → FN–HEAD FN–BODY P02: FN–HEAD → TYPE id ( PARAM–LIST ) P03: TYPE → char P04: TYPE → int P05: TYPE → real P06: PARAM–LIST → TYPE id P07: PARAM–LIST → PARAM–LIST , TYPE id P08: FN–BODY → { VAR–DECL STMT return ( EXPRESN ) ; } P09: VAR–DECL → λ P10: VAR–DECL → TYPE ID–LIST ; P11: VAR–DECL → VAR–DECL TYPE ID–LIST ; P12: ID–LIST → id P13: ID–LIST → ID–LIST , id P14: STMT → λ P15: STMT → SIMPLE–STMT P16: STMT → SELECT–STMT P17: STMT → REPEAT–STMT P18: STMT → SEQUENCE–STMT P19: SIMPLE–STMT → ASSIGN–STMT P20: SIMPLE–STMT → FN–CALL–STMT P21: ASSIGN–STMT → var = EXPRESN ; P22: EXPRESN → ARITH–EXP P23: EXPRESN → BOOL–EXP P24: ARITH–EXP → TERM P25: ARITH–EXP → ARITH–EXP ADD–OP TERM P26: ADD–OP → + P27: ADD–OP → – P28: TERM → FAC P29: TERM → TERM MUL–OP FAC P30: MUL–OP → *…
In this task you will work with the linked list of digits we have created in the lessons up to this point. As before you are provided with some code that you should not modify: A structure definition for the storage of each digit's information. A main() function to test your code. The functions createDigit(), append(), printNumber(), freeNumber(), readNumber() and divisibleByThree() (although you may not need to use all of these). Your task is to write a new function changeThrees() which takes as input a pointer that holds the address of the start of a linked list of digits. Your function should change all of those digits in this linked list that equal 3 to the digit 9, and count how many replacements were made. The function should return this number of replacements. Provided code
Please implement the follwoing problem in C++: Implement a symbol balance checker function for the Pascal programming language. Pascal allows for the following pairs: {}, (), [], begin end . All programs will begin with the word "begin" and end with the word "end". Your function should receive an ifstream object which is already open and will return true, all of the symbols match, or false, they do not. You do not have to worry about comments in the program but you do have to avoid other parts of the program's code such as assignment statements (x=y) and other expressions.
Log There was a storm recently on Jolibi village. The storm was so strong that some treesfell. There are some logs of varied length lying on the ground. The village ground canbe represented by a string of length N, where the i-th character is either 1 or 0. A singlelog is represented by consecutive characters of 1, and two different logs are separated byone or more 0. For example, for the string 1100010111, there are 3 logs. The first one atposition 1 to 2 with length 2, the second one at position 6 with length 1, and the thirdone at position 8 to 10 with length 3.As a carpenter, you want to take one of these logs home. Because you are the seniorcarpenter, you may take the longest log home. Determine the length of the longest log! Format InputThe first line contains an integer N, the length of the string. The next line contains a string of length N, which represents thevillage ground. Format OutputOutput an integer X, the length of the longest log. Constraints• 1 ≤ N ≤ 104• the i-th…
Consider the language consisting of all strings of properly balanced square brackets. The context freegrammar G is defined as follows:1. <Goal> ::= < List >2. <List> ::= < Pair > < List >3. <List> ::= ε4. <Pair> ::= [ <List> ]Note that EOF is the token that immediately follows the start symbol <Goal> and it means end offile (EOF), representing the end of an input sentence. Therefore you can assume FOLLOW{<Goal>} ={EOF}. (a) Give the FIRST sets of <List>, <Goal>, and <Pair>. (b) Give the FOLLOW set of <List>.
def reverse_sentence(s: str) -> str:"""Given a sentence <s>, we define a word within <s> to be a continuoussequence of characters in <s> that starts with a capital letter andends before the next capital letter in the string or at the end ofthe string, whichever comes first. A word can include a mixture ofpunctuation and spaces.This means that in the string 'ATest string!', there are in fact only twowords: 'A' and 'Test string!'. Again, keep in mind that words start with acapital letter and continue until the next capital letter or the end of thestring, which is why we consider 'Test string!' as one word.This function will reverse each word found in the string, and return a newstring with the reversed words, as illustrated in the doctest below.>>> reverse_sentence('ATest string!')'A!gnirts tseT' """ do it on python, and do not use any list, import or split, or append or join.