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Assuming the following: Warehouse 1 has outbound goods volume - 2,500 units Warehouse 2 has outbound goods volume - 1,300 units Warehouse 3 has outbound goods volume - 5,000 units Given the assumptions and grid coordinates above, the following: d1x= 200, d2x= 300, d3x= 100, d1y= 50, d2y= 100, d3y= 150 And V1= 2,500, V2= 1,300, V3= 5,000 Which is equal to: Cx= (200 x 2,500) + (300 x 1,300) + (100 x 5,000) / (2,500 + 1,300 + 5,000) = 158 Cy= (50 x 2,500) + (100 x 1,300) + (150 x 5,000) / (2,500 + 1,300 + 5,000) = 114   Use the numerical example set up above to demonstrate how the centre of gravity location technique is used.

Assuming the following: Warehouse 1 has outbound goods volume - 2,500 units Warehouse 2 has outbound goods volume - 1,300 units Warehouse 3 has outbound goods volume - 5,000 units Given the assumptions and grid coordinates above, the following: d1x= 200, d2x= 300, d3x= 100, d1y= 50, d2y= 100, d3y= 150 And V1= 2,500, V2= 1,300, V3= 5,000 Which is equal to: Cx= (200 x 2,500) + (300 x 1,300) + (100 x 5,000) / (2,500 + 1,300 + 5,000) = 158 Cy= (50 x 2,500) + (100 x 1,300) + (150 x 5,000) / (2,500 + 1,300 + 5,000) = 114   Use the numerical example set up above to demonstrate how the centre of gravity location technique is used.

Practical Management Science
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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Assuming the following:

Warehouse 1 has outbound goods volume - 2,500 units

Warehouse 2 has outbound goods volume - 1,300 units

Warehouse 3 has outbound goods volume - 5,000 units

Given the assumptions and grid coordinates above, the following:

d1x= 200, d2x= 300, d3x= 100, d1y= 50, d2y= 100, d3y= 150

And V1= 2,500, V2= 1,300, V3= 5,000

Which is equal to:

Cx= (200 x 2,500) + (300 x 1,300) + (100 x 5,000) / (2,500 + 1,300 + 5,000) = 158

Cy= (50 x 2,500) + (100 x 1,300) + (150 x 5,000) / (2,500 + 1,300 + 5,000) = 114

 

  1. Use the numerical example set up above to demonstrate how the centre of gravity location technique is used. 
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