Assuming the data given in the following table, calculate turbulence effect inhorizontal well for reservoir permeability K= 5 md.Pe2500 psiμZm(p)(psia)(cp)Pwf1500 psi0re3000ft14.7 0.998 0.0127 1.70E+040.3ft400 0.960 0.0130 1.28E+07h100ft8,000.925 0.0135 5.13E+071,200 0.895 0.0143 1.14E+08L1500 ftT150F10%1,600 0.873 0.0152 2.00E+082,000 0.860 0.0162 3.06E+082,250 0.856 0.0169 3.81E+082,500 0.857 0.0177 4.61E+082,750 0.860 0.0185 5.45E+083,000 0.867 0.0193 6.33E+080.02CP0.920.753,150 0.872 0.0197 6.87E+081ФHZYgWell Skin

Solution- ln (y-33) =6 t y -33 = e6t y=e6t +33

Answered: Assuming the data given in the…

Assuming the data given in the following table, calculate turbulence effect in horizontal well for reservoir permeability K= 5 md. Pe 2500 psi PZ m(p)

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter8: Stresses In A Soil Mass

Section: Chapter Questions

Problem 8.14P

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Concept explainers

Field applications of hydraulic conductivity

Hydraulic conductivity is one of the hydraulic properties of soil defined as a measurement of the ability of a porous medium to permit water movement or fluid flow through it. It is denoted by the letter K. It is influenced by the density and viscosity of the fluid. It is also called permeability. Hydraulic conductivity is defined as the ratio of velocity to the hydraulic gradient. The different methods used to determine the hydraulic conductivity are laboratory methods (constant head permeability tests and falling head tests), in-situ field methods (pumping in and pumping out tests), small scale field tests (infiltration tests and slug tests), and indirect methods such as estimation from grain size, consolidation test data, and horizontal capillary test. The pedotransfer function (PTF) method is a specific empirical estimating approach employed in the soil sciences is also used to determine the hydraulic conductivity of the soil.

Question

Assuming the data given in the following table, calculate turbulence effect in
horizontal well for reservoir permeability K= 5 md.
Pe
2500 psi
μ
Z
m(p)
(psia)
(cp)
Pwf
1500 psi
0
re
3000
ft
14.7 0.998 0.0127 1.70E+04
0.3
ft
400 0.960 0.0130 1.28E+07
h
100
ft
8,00
0.925 0.0135 5.13E+07
1,200 0.895 0.0143 1.14E+08
L
1500 ft
T
150
F
10
%
1,600 0.873 0.0152 2.00E+08
2,000 0.860 0.0162 3.06E+08
2,250 0.856 0.0169 3.81E+08
2,500 0.857 0.0177 4.61E+08
2,750 0.860 0.0185 5.45E+08
3,000 0.867 0.0193 6.33E+08
0.02
CP
0.92
0.75
3,150 0.872 0.0197 6.87E+08
1
Ф
H
Z
Yg
Well Skin

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