Answered: Assuming an efficiency of 38.70%,…

Assuming an efficiency of 38.70%, calculate the actual yield of magnesium nitrate formed from 136.2 g of magnesium and excess copper(II) nitrate. Mg + Cu(NO,), –→ Mg(NO,),+Cu actual yield: g

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Assuming an efficiency of 38.70%, calculate the actual yield of magnesium nitrate formed from 136.2 g of magnesium and
excess copper(II) nitrate.
Mg + Cu(NO,),
Mg(NO,),+Cu
actual yield:

Expert Solution

Step 1

The given chemical equation is as follows:

$Mg + Cu {({NO}_{3})}_{2} \to Mg {({NO}_{3})}_{2} + Cu$

The efficiency of the reaction = 38.70 %

The given mass of Mg = 136.2 g

The actual yield of the $Mg {({NO}_{3})}_{2}$ =?

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