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Assume we have the following a system of linear equation. 21 – 2x2 = 3 3x1 - 4x2 = 7 Then the exact solution is ærs = (1, –1). Let an approximate solution rNS = (-2, -4). Then, residual (= backward error) = error (= forward error) = error magnification factor =

Assume we have the following a system of linear equation. 21 – 2x2 = 3 3x1 - 4x2 = 7 Then the exact solution is ærs = (1, –1). Let an approximate solution rNS = (-2, -4). Then, residual (= backward error) = error (= forward error) = error magnification factor =

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Assume we have the following a system of linear equation. Jx1 – 2x2 = 3 | 3x1 – 4x2 = 7 Then the exact solution is rTs = (1, –1). Let an approximate solution rNS = (-2,–4). %3D Then, residual (= backward error) error (= forward error) = error magnification factor =
Transcribed Image Text:Assume we have the following a system of linear equation. Jx1 – 2x2 = 3 | 3x1 – 4x2 = 7 Then the exact solution is rTs = (1, –1). Let an approximate solution rNS = (-2,–4). %3D Then, residual (= backward error) error (= forward error) = error magnification factor =
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