Assume this simple Dryad topology: A-> B. If task B crashes, will both tasks have to be re-executed? Justify your answer.
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Assume this simple Dryad topology: A-> B. If task B crashes, will both tasks have to be re-executed? Justify your answer.
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- Wireless sensor networks (WSNs) are an example of a network that may facilitate communication. Sensing nodes in WSNs communicate with one another and a central hub. The computing resources and storage space of a sensor node are limited. Think of an algorithm that can be solved by separating it into smaller chunks. To solve these subproblems at separate sensor nodes, would you prefer use divide and conquer or dynamic programming? Please be brief in your writing.Wireless sensor networks are a type of communication network. In WSNs, sensor nodes are responsible for relaying information to and from other nodes and a central base station. Typically, a sensor node has limited resources, such as processing speed and storage space. Take a algorithm that can be decomposed into simpler issues. To solve these subproblems at separate sensor nodes, would you rather use divide and conquer or dynamic programming? Use succinct language.Given that you have submitted many requests to a server, each with its own id (or unique identification) and priority (or priority).Requests = [(id1, p1), (id2, p2), ……, (idn, pn)], where p1 > p2 > …. > pn. Provide the best algorithm or pseudocode for dealing with all of the requests.
- P is a set of processes. R is a set of resources. E is a set of request or assignment edges. The sets P, R,and E are as follows:P = {P1, P2, P3}R = {R1, R2, R3}E = {P1 -> R1, P2 -> R3, P3-> R2, R1 -> P2, R2 -> P2, R2 -> P1, R3 -> P3}R1 has one instance. R2 has two instances. R3 has one instance.a. Explain clearly with the help of a properly labelled diagram what is a resource allocation graph?Draw the resource-allocation graph for the given case also. [2 + 1]b. Is there any deadlock in this situation? Explain your answer clearly.Solve the following problem using Scala with Classic Akka Actors. For each problem, also implement client actors for sending the messages required for beginning the required computation. Use these client actors for testing your application actors. Read the submission instructions carefully. Sorting. It is possible to sort a number of values using a pipeline of filter actors, each responsible for one value: the first actor picks the smallest value, the second the second smallest and so on. Particularly, the first actor receives all the values, one by one. If there are more than one values received by an actor, it creates another actor; it keeps the smallest value received so far for itself, and sends all other values forward to the actor it created. Each filter actor does the same thing. Assume that each filter actor has local storage for only two of the values to be sorted: the next incoming value and the minimum value seen thus far. A sentinel is used to indicate the end of the values…ARENA is a multi-user, Web-based system for organizing and conducting tournaments. ARENA is game independent in the sense that organizers can adapt a new game to the ARENA game interface, upload it to the ARENA server, and immediately announce and conduct tournaments with players and spectators located anywhere on the Internet. Organizers can also define new tournament styles, describing how players are mapped to a set of matches and how to compute an overall ranking of players by adding up their victories and losses (hence, figuring out who won the tournament). To recoup their operational costs, organizers can also invite potential sponsors to display advertisement banners during games. USE-CASE DIAGRAM: A. Identify Actors and Use Cases for the Arena Game System. Draw the Use Case Diagram that details the high-level functionality of the system. Make sure to have includes and extends relationships between use cases where relevant. B. Pick any 2 use cases from your diagram and provide…
- P is a set of processes. R is a set of resources. E is a set of request or assignment edges. The sets P, R, and E are as follows: P = {P1, P2, P3} R = {R1, R2, R3} E = {P1 -> R1, P2 -> R3, P3-> R2, R1 -> P2, R2 -> P2, R2 -> P1, R3 -> P3} R1 has one instance. R2 has two instances. R3 has one instance. a. Explain clearly with the help of a properly labelled diagram what is a resource allocation graph? Draw the resource-allocation graph for the given case also. b. Is there any deadlock in this situation? Explain your answer clearly.Wireless sensor networks (WSNs) are an example of a network that may facilitate communication. Sensing nodes in WSNS communicate with one another and a central hub. The computing resources and storage space of a sensor node are limited. Think of an algorithm that can be solved by separating it into smaller chunks. To solve these subproblems at separate sensor nodes, would you prefer use divide and conquer or dynamic programming? Please be brief in your writing.Translate these specifications in to English where F(p) is "Printer p is out of service, B(p) is "Printer p is busy." L(j) is "Print job j is lost," and QG) is "Print job j is queued." (a) Ep(F(p)^ B(p))→jL(j) (b) VpB(p)→3jQ(j) (c) )^ L(j))→apF(p)
- You can use URLs to access information on the Web from within Java programmes. (uniform resource locators). MindSlave software programmers (working on their new NetPotato browser) want to maintain track of a potentially enormous bookmark list of frequently visited URLs. It would be ideal if they could have arbitrary access to the values saved in the list. Is a List a suitable data structure? (Tip: If not, why not?)Simulate any rounting algorithm for MANET. Your simulation MUST include the following: - The sinarion where you show the whole topolgoy of the network (Nodes and links). - Route discovery process. - Route Replay and error. Coding in c++You can use URLs to access information on the Web from Java programmes. (uniform resource locators). Programmers at MindSlave Software would like to manage a potentially sizable bookmark list of frequently visited URLs for their new NetPotato browser. They would find it most helpful if they had unrestricted access to the list's preserved values. Is a List the right kind of data structure? If not, why not? (Hint: