Assume the variables a = 2, b = 4, and c = 6. state true or false. !(a > 2)

Using C++ programming language: Use the if construct to check a range. Assume the variables height and width are already defined as integers. Write the if statement that evaluates to true if and only if the height is greater than 50 and the width is less than 10.

Problem Statement Write a program that reads three positive integers (>0)from the command line (one at a time), then computes and prints the smallest entered number. Use if-else statements for three integer comparison. Assuming that the use always enter a valid positive integer. Example 1: Enter an integer: 5 Enter an integer: 23 Enter an integer: 7 The smallest number is: 5 Example 2: Enter an integer: 3 Enter an integer: 3 Enter an integer: 6 The smallest number is: 3 Partial Solution Please try to implement the full source code in your IDE first. The solution is partially provided below. Fill in the blanks to complete the missing parts and make sure to not add an empty space before and after the answer. #include using namespace std; int main() ( //decare three Intergersvariables Int first, second, third, smallest; //prompt and get user inputs cout> first cout> second cout> third //find the smallest number [Select] second) [Select] (first [Select] third) X smallest [Select] Jelse if…

Take a screenshot of your output. write a C++ functions to compute following (Set Theory)  #include <iostream>#include <vector>using namespace std;struct rpair {int a;int b;}; void print(std::vector<struct rpair>& R) {for (auto e: R) {cout<<e.a <<" " << e.b <<endl;} } std::vector<int> composition(std::vector<struct rpair>& R, std::vector<struct rpair>& S){} std::vector<struct rpair> cartesian_product(std::vector<int>& a, std::vector<int>& b) { }   int main(){//struct rpair x = {10,20};int x = 128;printf("%c\n", x);std::vector<struct rpair> R = {{1, 2}, {1, 6}, {2, 4}, {3, 4}, {3, 6}, {3, 8}};std::vector<struct rpair> S = {{2, 'u'}, {4, 's'}, {4, 't'}, {6, 't'}, {8, 'u'}}; print(R); return 0;}