Assume the pe of the surface water of a lake is controlled by the O,/H,O half-reaction. What would the concentration of ferrous iron (Fe2") be in the system if it has a pH of 8 and it is in equilibrium with the atmosphere (Po2 = 0.21 atm)? Assume the temperature is 25 °C. log K pe O2(g) + 4H* + 4e = 2H2O 83.1 20.78 FEOOH(s) + 3H* + e = Fe2* + 2H20 13.5 13.50

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Assume the pe of the surface water of a lake is controlled by the O2/H2O half-reaction. What would the
concentration of ferrous iron (Fe2") be in the system if it has a pH of 8 and it is in equilibrium with the
atmosphere (Po2 = 0.21 atm)? Assume the temperature is 25 °C.
log K
pe
O2(g) + 4H* + 4e" = 2H,0
83.1
20.78
FEOOH(s) + 3H* + e = Fe2* + 2H2O
13.5
13.50
Transcribed Image Text:Assume the pe of the surface water of a lake is controlled by the O2/H2O half-reaction. What would the concentration of ferrous iron (Fe2") be in the system if it has a pH of 8 and it is in equilibrium with the atmosphere (Po2 = 0.21 atm)? Assume the temperature is 25 °C. log K pe O2(g) + 4H* + 4e" = 2H,0 83.1 20.78 FEOOH(s) + 3H* + e = Fe2* + 2H2O 13.5 13.50
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