Assume that when human resource managers are randomly​ selected, 51​% say job applicants should follow up within two weeks. If 8 human resource managers are randomly​ selected, find the probability that exactly 6 of them say job applicants should follow up within two weeks.

Here the given information is

Assume that when human resource managers are randomly​ selected, 51​% say job applicants should follow up within two weeks. If 8 human resource managers are randomly​ selected.

The given problem can be modeled using the binomial probability distribution.

Let X be the binomial random variable with parameters n and p, where "n" represents the total number of human resource managers randomly selected and "p" represents the probability that the selected human resource manager say job applicants should follow up within two weeks.

Also As we know, for a binomial distribution, the probability of "m" successes is computed as -

  P(x=m) = ( n!/m!(n-m)! ) (P)^m(1-p)^n-m