Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value t/2. (b) find the critical value z12, or (c) state that neither the normal distribution nor the t distribution applies. 40- 30- The confidence level is 95%, o = 3697 thousand dollars, and the histogram of 58 player salaries (in thousands of dollars) of football players on a team is as shown. 20- 10- 0- 4000 8000 120o0 1600 20000 Salary (thousands of dollars) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. tu/2= (Round to two decimal places as needed.) O B. Za12 = (Round to two decimal places as needed.) O C. Neither the normal distribution nor the t distribution applies.

Calculate the margin of error of a confidence interval for the difference between two population means using the given information. Round your answer to six decimal places. σ1=13.77, n1=87, σ2=10.46, n2=96n, c=0.95

A statistics class is estimating the mean height of all female students at their college. They collect a random sample of 42 female students and measure their heights. The mean of the sample is 65.3 inches and the sample standard deviation is 5.4 inches. Find the 90% confidence interval for the mean height of all female students in their school? Assume that the distribution of individual female heights at this school is approximately normal. 1. The t value is 1.3025 2. The standard error has a value of -- 3. The margin of error has a value of 4. Find the 90% confidence interval for the mean height of all female students in their school

Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 17. (Round your answer to three decimal places.)

Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96

Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 29. (Round your answer to three decimal places.)

The interval [40 50] represents a 90% confidence interval for a population mean. Which of the following is most likely to be the corresponding 95% confidence interval? (Hint: in a normal distribution, close to 90% of the values are within 1.65 standard deviations of the mean and close to 95% of the values are within 2 standard deviations of the mean) O A. [42 48] В. [36 54] OC. [40 54] D. [30 60]