Assume that the total cholesterol levels for adults are normally distributed with mean cholesterol level of 51.8 mg/dL and standard deviation 14.3 mg/dL. Find theprobability that an individual will have a cholesterol level greater than 58 mg/dL.Click here for page 1 of the Areas under the Normal Curve TableClick here for page 2 of the Areas under the Normal Curve Table.....The probability that an individual will have a cholesterol level greater than 58 mg/dL is(Round to four decimal places as needed.)

Given data: Mean = 51.8 mg/dL Standard deviation = 14.3 mg/dL To find: Find the probability that…

Answered: Assume that the total cholesterol…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Describe the difference in shape between a gamma(shape = 5, rate= 10) distribution and a beta(shape = 10, rate= 5) distribution. I.e., are the skew, mean, and interquartile ranges of the two distributions the same, and if one is larger, which one?
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If the area to the left of æ in a normal distribution is 0.796, what is the area to the right of x? Answer: If the area to the right of x in a normal distribution is 0.796, what is the area to the left of x? Answer: Question Help: DPost to forum E Calculator Submit Question étv ... MacBook Air 000 esc F4 F5
Until your a For a recent 10k run, the finishers are normally distributed with mean 63 minutes and standard deviation 14 minutes. Complete parts (a) through (d) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. ... a. Determine the percentage of finishers with times between 45 and 75 minutes. Approximately 70.50 % of finishers had times between 45 and 75 minutes. (Round to two decimal places as needed.) b. Determine the percentage of finishers with times less than 80 minutes. torre Que Approximately % of finishers had times less than 80 minutes. (Round to two decimal places as needed.) ✔Question 1 (1 Question 5 (0 Name: Due: Last Worked: Current Score: Attempts:
According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1,100 Americans results in 121 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). O B. This is not necessarily evidence that the proportion of Americans who are afraid to fly has increased above 0.10 because the probability of obtaining a value equal to or more extreme than the sample proportion is which is not unusual. (Round to four decimal places as needed.)
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The mean performance score of a large group of fifth-grade students on a math achievement test is 76. The scores are known to be normally distributed. What percentage of the students had scores more than 2.1 standard deviations above the mean? Click here for page 1 of the Areas under the Normal Curve Table Click here for page 2 of the Areas under the Normal Curve Table The percentage of the students that had scores more than 2.1 standard deviations above the mean is%. (Round to two decimal places as needed.)
You can tell if a distribution is normal because it is Approximately bell-shaped and symmetrical Skewed to the right or left Empirical and statistically significant Independent
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