Assume that the random vanable X is normally distributed, with mean = 60 and standard deviation o=16. Compute the probability P(X<80) O 0.8944 0.1056 0.8849 O 0.9015
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- The probability function for the number of seizures, X, of a typical epileptic person in any given year is given in the following table. Calculate the standard deviation in the number of seizures is x 0 2 4 6 f(x) 0.17 0.21 0.18 0.11 0.16 0.17 8 10 4.11 None of the choices 5.07 О 347Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with a mean of 160.5 ft and a standard deviation of 9.7 ft. A tree of this type grows in my backyard, and it stands 162.4 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter. P(X 169.2) = Enter your answers as decimals accurate to 4 decimal places.Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -2.828°C and 0.913°C. P( – 2.828 < Z < 0.913)
- Suppose that X follows a binomial distribution with n = 100 and p = 0.1. If F(x) is the cumulative distribution function of the Standard Normal distribution. Then using the Normal approximation, the probability P(X = 16) is obtained by O a. F(2.17) - F(1.83) O b. F(1.83) - F(2.17) O c. F(16.5) + F(15.5) O d. F(17.0) - F(15.0)Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with μ=8.2ft and σ=38.8ftYou intend to measure a random sample of n=83 trees What is the mean of the distribution of sample means? What is the standard deviation of the distribution of sample means (i.e., the standard error in estimating the mean)? What is the probability that the average height of a random sample of 83 trees is larger than 9.4? Round answer to 4 decimal places.Assume that the random variable X is normally distributed, with mean p1 = 70 and standard deviation o= 12. Compute the probability P(X< 85). 0000 0.1056 0.9015 0.8849 0.8944 C
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