Assume that R, S, and T are regular expressions and ε is the empty string and is the empty set. Select all the identities of that are correct: 0 ω * * = 0 = 0 Q * = ω ☐ ω * = ε (R*)* = R ☐ R. R+ = R * ε + R.R* = R * |(R.S)* .R = R. (R.S)* (R+S)* = (R*. S*)*
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- Give an example of a set with three elements, each of which is aset.Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; M = {3, 5, 7, 9, 10}; N = {3, 4, 9, 10}; and O = {6, 7,8, 9, 10}. List the members of the indicated set, using set braces:(i) (N nO)'(ii) M u (N - O)(iii) MΔO(iv) M n N’nOdef longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab' >>> longest_unique_substring('abcabcbb')'abc'"""
- def longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab' >>> longest_unique_substring('abcabcbb')'abc'""" RESTRICTIONS: - Do not add any imports and do it on python .Do not use recursion. Do not use break/continue.Do not use try-except statements.def longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab'""" RESTRICTIONS: - Do not add any imports and do it on python .Do not use recursion. Do not use break/continue.Do not use try-except statements.Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] """ def generate_parenthesis_v1(n): defadd_pair(res, s, left, right): ifleft==0andright==0: res.append(s) return ifright>0: add_pair(res, s+")", left, right-1) ifleft>0: add_pair(res, s+"(", left-1, right+1) res= [] add_pair(res, "", n, 0) returnres def generate_parenthesis_v2(n): defadd_pair(res, s, left, right): ifleft==0andright==0: res.append(s) ifleft>0: add_pair(res, s+"(", left-1, right) ifright>0andleft<right: add_pair(res, s+")", left, right-1).
- Given subsets A and B of a universal set with 10 elements {0, 1, 2, 3, 4, 5, 6, 7, 8,9}. Write a C++ or Java program that uses bit strings to find A È B, A Ç B, and A – B. Print tothe screen set A, set B ( be sure to print out the name of the sets), as well as the set operation results(be sure to print out the name of the operations).The program requires that elements of subsets A and B are from user input. You can make theassumption that user input numbers are within the domain of the set {0, 1, 2, ..., 9} and there isno improper input.Additional requirements and reminders:• The use of STL, templates, and operator overloading is not permitted in any form.• Remember: You must use a bit string when representing a set. You may not use an array ofBoolean variables.• The elements of subset A and subset B must from user input. You may not hardcode the twosubsets in your program.A cryptarithm is a mathematical puzzle for which the goal is to find the correspondence between letters and digits, such that the given arithmetic equation consisting of letters holds true when the letters are converted to digits. You have an array of strings crypt, the cryptarithm, and an an array containing the mapping of letters and digits, solution. The array crypt will contain three non-empty strings that follow the structure: [word1, word2, word3], which should be interpreted as the word1 + word2 = word3 cryptarithm. If crypt, when it is decoded by replacing all of the letters in the cryptarithm with digits using the mapping in solution, becomes a valid arithmetic equation containing no numbers with leading zeroes, the answer is true. If it does not become a valid arithmetic solution, the answer is false. Note that number 0 doesn't contain leading zeroes (while for example 00 or 0123 do).Given A = {a, b, c}, B = {0,1}, and C = {m, n}, write down the elements of B × C × A(note order of sets):
- solve in C please. Implement the following two functions that get a string, and compute an array of non-emptytokens of the string containing only lower-case letters. For example:● For a string "abc EFaG hi", the list of tokens with only lower-case letters is ["abc", "hi"].● For a string "ab 12 ef hi ", the list of such tokens is ["ab","ef","hi"].● For a string "abc 12EFG hi ", the list of such tokens is ["abc","hi"].● For a string " abc ", the list of such tokens is ["abc"].● For a string "+*abc!! B" the list of such tokens is empty.That is, we break the string using the spaces as delimiters (ascii value 32), and look only at thetokens with lower-case letters only .1. The function count_tokens gets a string str, and returns the number ofsuch tokens.int count_tokens(const char* str);For example● count_tokens("abc EFaG hi") needs to return 2.● count_tokens("ab 12 ef hi") needs to return 3.● count_tokens("ab12ef+") needs to return 0.2. The function get_tokens gets a string str, and…C. _______ the set of all subsets of a set including the empty set and the set itself.Given an array of strings, return all groups of strings that are anagrams. The groups must be created in order of their appearance in the original array. Look at the sample case for clarification. Note: The final output will be in lexicographic order. Example 1: Input:N = 5words[] = {act,god,cat,dog,tac}Output:act cat tac god dogExplanation:There are 2 groups ofanagrams "god", "dog" make group 1."act", "cat", "tac" make group 2.