Assume that events X, Y, Z are mutually exclusive (pairwise) and P(X) = 0.132 P(Y) = 0.1618 P(Z) = 0.0784 then what is P(X ∪ Y ∪ Z) = the probability of X or Y or Z? Give four digits past the decimal point

Assume that events X, Y, Z are mutually exclusive (pairwise) and P(X) = 0.132 P(Y) = 0.1618 P(Z) = 0.0784 then what is P(X ∪ Y ∪ Z) = the probability of X or Y or Z? Give four digits past the decimal point

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

Assume that events X, Y, Z are mutually exclusive (pairwise) and

P(X) = 0.132

P(Y) = 0.1618

P(Z) = 0.0784

then what is P(X ∪ Y ∪ Z) = the probability of X or Y or Z?

Give four digits past the decimal point.

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