Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 375 with 268 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. C.I. =

Q: Assume that population proportion is to be estimated from the sample described. Use the sample…

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Q: Suppose a 95% confidence interval for a population proportion is found using the theory-based…

A: given data  95% ci for p  using theory based method. what it contains defenately from given options?…

Q: Use the Student's t distribution to find t, for a 0.95 confidence level when the sample is 27.

A: sample size=n=27 Degree of Freedom=n-1=27-1 =26 Confidence level is 0.95 Therefore the Level of…

Q: Use the given data to construct a 98%confidence interval for the population proportion p x = 52 , n…

A: We have given that,  Favorable cases (X) = 52 and sample size (n) = 69 Then,  We will find the 98%…

Q: Prove that if B (is included in) A, THEN P(B) < P(A)

A: Given :  Set B is included in set A To Prove : P(B) &lt; P(A)

Q: Assume that population proportion is to be estimated from the sample described. Use the sample…

A: sample size(n)=515sample proportion=0.20Confidence level=95%

Q: For a sampling distribution of n = 1500 and population proportion of 0.42 of those who prefer…

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Q: Find the indicated margin of error. Out of 260 trials, 150 turned out positive. Find the margin of…

A: It is given that the sample size (n) is 260 and the number of positive trials (x) is 150.

Q: Find the indicated margin of error. Out of 330 trials, 150 turned out positive. Find the margin of…

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Q: d. FIND t a n = 10 for the 90% confidence interval for the mean. %3D

A: d. Given: n=10 α=0.1 The degrees of freedom is obtained as below: df=n-1=10-1=9 Critical value: The…

Q: A random sample of 600 adults in Flagstaff found 90 adults who had lost a job in the past year. Find…

A: Step 1:Given data : Sample size n=600no. of successes x=90   Sample proportion p^​=60090​=0.15Let p…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: Find the margin of error for the 95% confidence interval used to estimate the population proportion.…

A: Confidence level = 95% Sample size (n) = 2440 Sample proportion (p̂) = 0.70

Q: For a sampling distribution of n = 500 and population proportion of 0.48 of those who prefer cookies…

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Q: if ue want a 96%. confidence nterval on populatron mean with a sample size of a3, find or 土

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Q: Find the condence level and a for a. a 90% confidence interval.b. a 99% confidence interval.

A: a.The confidence level and α for a 90% confidence interval is obtained below:The confidence level is…

Q: Assume that population proportion is to be estimated from the sample described. Use the sample…

A: Givensample size(n)=565sample proportion(p^)=0.2α=1-0.95=0.05α2=0.025zc=zα2=z0.025=1.96   (from z…

Q: Determine the minimum sample size needed if we want to estimate the population percent of students…

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Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Margin of error (E) for proportion is defined as below                                E = Width2…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?

Q: If X 121, o =27, and n 38, construct a 95% confidence interval estimate of the population mean, u.…

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Q: If n=27, x=48, and s-6, construct a confidence interval at a 80% confidence level. Assume the data…

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Q: A confidence interval was constructed to approximate a population proportion. The interval was from…

A: We have given that,  Let p̂ represents the sample proportion and E represents the margin of error,…

Q: Use the given data to construct a confidence interval of the requested level. X = 178, N=531,…

A: Given : Sample Size, n = N = 531 Number of successes, x = 178

Q: If n=30, 7(x-bar)=49, and s=14, construct a confidence interval at a 99% confidence level. Assume…

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Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: In a survey of 2105 adults in a recent year, 737 made a New Year's resolution to eat healthier.…

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Q: If n = 380 and X = 304, construct a 95% confidence interval for the population proportion, p. Give…

A: Given: n = 380 x = 304

Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that…

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Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that…

A: The question is about confidence interval.Given :No. of selected observations ( n ) = 1400Sample…

Q: Use the confidence interval to find the margin of error and the sample mean. (12, 20) O E = 4, X =…

A: confidence interval for mean : (12,20)

Q: American Airlines' flights from Boston to Dallas are on time 90 % of the time. Suppose 8 flights are…

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Q: For a sampling distribution of n = 800 and population proportion of 0.42 of those who prefer cookies…

A: We have find distribution...

Q: In a survey of 2000 adults in a recent year, 713 made a New Year's resolution to eat healthier.…

A: We have given that  Sample size n= 2000 Favorable cases x = 713 Sample proportion p^=x/n

Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…

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Q: Assume that a sample is used to estimate a population proportion p. To find the 95% confidence…

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Q: If n = 220 and X = 176, construct a 95% confidence interval for the population proportion, p. Give…

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Q: In a survey of 2445 adults in a recent​ year, 1491 say they have made a New​ Year's resolution.…

A: From the given information, let X be the number of adults have made a New Year’s resolution. X =…

Q: ou are given the smaple mean and the population m standard deviation. Use this info to construct the…

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Q: In a survey of 6700 T.V. viewers, 3350 said they watch network news programs. Find the margin of…

A: n = 6700 x = 3350  p̂ = x/n = 3350/6700 = 0.50Confidence level (c) = 99% = 0.99Significance level…

Q: Find the sample size need to find the Population Proportion if the margin of error is 4%, the…

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Q: It is desired to estimate the proportion of cannabis users at a university. What is the sample size…

A: Here, CL=0.95 and E=0.10.

Q: Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she…

A: From the provided information, The data values are as follow: 9, 12, 13, 10 and 10 Sample size (n) =…

Q: If [0.64, 0.82] is a confidence interval for the population proporlion. Find the value of the point…

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