MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Three friends are having a debate. They recently read that on average Americans drive 16 miles each way when computing to work by car (ABC News, 2007). Friend A suspects that the mean for Colorado residents is likely lower than the national average because the population density of Colorado increases the likelihood that people live closer to their jobs, while friend B suspects the mean for Colorado residents is likely higher than the national average. Friend C does not find either argument very convincing and instead suspects that the mean for Colorado residents is no different from the US population mean. The three friends bet a dinner at Alinea and set out to resolve the debate. Using a random sample of 20 Colorado residents, they calculate the mean for their sample to be 14.23 miles with a standard deviation of 2.34. The three friends did not pay very close attention in their statistics class, so they need your help making sense of these numbers. Compute the 95% confidence…arrow_forwardShow the steps on how to solve this problem along with the answerarrow_forwardMichelle, a student studying music, randomly sampled fellow music majors and asked whether they listen to music while they study. The resulting confidence interval for the proportion of music students who listen to music while studying is (0.09, 0.26). What is the margin of error?arrow_forward
- 99 students at a college were asked whether they had completed their required English 101 course, and 63 students said "yes". Construct the 80% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.arrow_forwarda) Determine 95% and 99% confidence limits for the proportion male students who feel “wealthwas necessary for happiness.” b) Determine 95% and 99% confidence limits for the proportion female students who feel “wealthwas necessary for happiness.” c) Determine 95% and 99% confidence limits for the difference in proportions between male students and female students who feel “wealth was necessary for happiness.” I have only posted three subparts as you allow only three subparts of question.arrow_forwardIn a survey of 952 respondents, 620 of them voted in a recent election. Find a 95% confidence interval estimate for the true population proportion that voted in this election.arrow_forward
- Suppose that there is a 15% chance that a randomly selected Stat 240 student wears glasses. Out of a class with 35 students, what is the minimum number of students wearing glasses for the percent to be considered unusually high? Thanks!arrow_forwardAn online instructor wants to estimate the mean amount of time that students spend in the online homework system on a particular homework assignment. The instructor takes a random sample of 30 students and looks up the amount of time recorded by the system for that assignment.arrow_forwardA local cellular phone company wishes to estimate the proportion of Clinton County people who own a cellular phone. A previous study showed the proportion to be about 25%. What is the minimum number of people that should be randomly selected so the cellular company is 95% confident that the estimate is within 5% of the true proportion of cellular phone users?arrow_forward
- A statistics content developer at Aplia wanted to know whether study skills are related to memory quality. She invited student volunteers to perform an online memory task. The students saw a list of 60 words and were then asked to recognize a list of 10 words that were on the original list. Students were also asked to provide their GPAs. Consider the following data set, which was collected from student volunteers in 2009. The table gives the frequency for five intervals of scores on the number of correctly identified words. Use the dropdown menus to complete the table by filling in the missing values for the proportions and percentages. Score Interval f Proportion Percentage 9–10 29 0.19 19% 7–8 53 5–6 50 3–4 22 0.14 14% 1–2 1 0.01 1%arrow_forwardSuppose 500 different researchers all randomly select samples of n = 300 individuals from a population. Each researcher uses his or her sample to compute a 95% confidence interval for the proportion who have blue eyes in the population. About how many of the confidence intervals will cover the population proportion? About how many of the intervals will not cover the population proportion? Briefly explain how you determined your answers. About About which is % of the 500 computed intervals, should contain the population proportion. which is % of the 500 computed intervals, should not contain the population proportion.arrow_forwardhelparrow_forward
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