Assume that a ball of charged particles has a uniformly distributed negative charge density except for a narrow radial tunnel through its center, from the surface on one side to the surface on the opposite side. Also assume that we can position a proton anywhere along the tunnel or outside the ball. Let FR be the magnitude of the electrostatic force on the proton when it is located at the ball's surface, at radius R. As a multiple of R, how far from the surface is there a point where the force magnitude is 0.65FR if we move the proton (a) away from the ball and (b) into the tunnel? X (a) Number 1.24 Units This answer har

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Assume that a ball of charged particles has a uniformly distributed negative charge density except for a narrow radial tunnel through its center, from the surface on one
side to the surface on the opposite side. Also assume that we can position a proton anywhere along the tunnel or outside the ball. Let FR be the magnitude of the
electrostatic force on the proton when it is located at the ball's surface, at radius R. As a multiple of R, how far from the surface is there a point where the force
magnitude is 0.65FR if we move the proton (a) away from the ball and (b) into the tunnel?
(a) Number
Units
1.24
This answer has no units
(b) Number
Units
.51
This answer has no units ▼
Click if you would like to Show Work for this question: Open Show Work
Transcribed Image Text:Assume that a ball of charged particles has a uniformly distributed negative charge density except for a narrow radial tunnel through its center, from the surface on one side to the surface on the opposite side. Also assume that we can position a proton anywhere along the tunnel or outside the ball. Let FR be the magnitude of the electrostatic force on the proton when it is located at the ball's surface, at radius R. As a multiple of R, how far from the surface is there a point where the force magnitude is 0.65FR if we move the proton (a) away from the ball and (b) into the tunnel? (a) Number Units 1.24 This answer has no units (b) Number Units .51 This answer has no units ▼ Click if you would like to Show Work for this question: Open Show Work
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