Assume steady-state, unidirectional conductive heat transfer in the s-direction for the shape shown below. The area available for conduction changes with s according to the formula: A(s) = 0.01s2. A s1=0.02m, T=300K and at s2=0.05m T=100K. The conductivity k=10 W/m-K. TH To adiabatic Derive the governing differential equation for temperature T in terms of the parameters given in the problem statement What are the boundary conditions for the problem? Solve the differential equation to determine T(s) and plot the results a. b. с.

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
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Chapter4: Numerical Analysis Of Heat Conduction
Section: Chapter Questions
Problem 4.19P
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A b c

3.
Assume steady-state, unidirectional conductive heat transfer in the s-direction for the shape
shown below. The area available for conduction changes with s according to the formula: A(s)
0.01s?. A s1=0.02m, T=300K and at s2=0.05m T=100K. The conductivity k=10 W/m-K.
T,
Tc
adiabatic
Derive the governing differential equation for temperature T in terms of the parameters
given in the problem statement
What are the boundary conditions for the problem?
Solve the differential equation to determine T(s) and plot the results
What is the heat flux at s1 and s2?
а.
b.
С.
d.
е.
What is the heat transferred at s1 and s2?
Transcribed Image Text:3. Assume steady-state, unidirectional conductive heat transfer in the s-direction for the shape shown below. The area available for conduction changes with s according to the formula: A(s) 0.01s?. A s1=0.02m, T=300K and at s2=0.05m T=100K. The conductivity k=10 W/m-K. T, Tc adiabatic Derive the governing differential equation for temperature T in terms of the parameters given in the problem statement What are the boundary conditions for the problem? Solve the differential equation to determine T(s) and plot the results What is the heat flux at s1 and s2? а. b. С. d. е. What is the heat transferred at s1 and s2?
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