College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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As you will see in a later chapter, forces are vector quantities, and the total force on an object is the vector sum of all forces acting on it.
In the figure below, a force ₁ of magnitude 6.80 units acts on a box at the origin in a direction 0 = 29.0° above the positive x-axis. A second force F2 of magnitude 5.00 units acts on the box in the direction of
the positive y-axis. Find graphically the magnitude and direction (in degrees counterclockwise from the +x-axis) of the resultant force ₁ + F2.
magnitude
direction
F₂
F₁
i
units
° counterclockwise from the +x-axis
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Transcribed Image Text:As you will see in a later chapter, forces are vector quantities, and the total force on an object is the vector sum of all forces acting on it. In the figure below, a force ₁ of magnitude 6.80 units acts on a box at the origin in a direction 0 = 29.0° above the positive x-axis. A second force F2 of magnitude 5.00 units acts on the box in the direction of the positive y-axis. Find graphically the magnitude and direction (in degrees counterclockwise from the +x-axis) of the resultant force ₁ + F2. magnitude direction F₂ F₁ i units ° counterclockwise from the +x-axis
Expert Solution
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Step 1

Here, 

F1 = 6.80 units

θ = 29.0o

So,

X-component of F1 = 6.80*cos29 = 5.947 N

Y-component of F1 = 6.80*sin29 = 3.296 N

 

F2 = 5 N

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