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- Needs Complete typed solution with 100 % accuracy.arrow_forwardConsider the configuration of two charged parallel plates shown below. How will the electric potential (V) at points A and B compare for this system? B A. A = high potential and B = low potential B. A = low potential and B = high potential C. A = high potential and B = high potential D. A = low potential and B = low potential %3D + + + + tarrow_forwardA From Equation 25.6, we have the following. AV = -Ed = -(7.2 × 104 v/m)(0.60 m) = B V From Equation 25.3, we have the following. AU = qAV = eAV = (1.6 x 10-19 C)(AV) | The negative sign means that the potential energy of the system decreases as the proton moves in the direction of the electric field. This decrease is consistent with the conservation of energy in an isolated system: as the proton accelerates in the direction of the field, it gains kinetic energy and at the same time the system loses electric potential energy. The increase in kinetic energy of a charged particle in an electric field is exploited in many devices, including electron guns for TV picture tubes and particle accelerators for research in particle physics. You can predict and observe the speed of the proton as it arrives at the negative plate for random values of the electric field using this Interactive Example. Hints: Getting Started | I'm Stuck Exercise 25.2 For the previous example, apply the principle of…arrow_forward
- Capacitor A is a standard parallel-plate capacitor with no dielectric. It was charged up (though is currently not attached to anything) and currently has charge of Qo, a voltage of Vo, a capacitance of Co, and a potential energy of PE,. A dielectric with K = 41 is to be inserted into capacitor A. Determine what the capacitance, charge, voltage, & potential energy of capacitor A will be once the dielectric is fully inserted. C = C,x 41 Q = Q,x 1 V = V,x PE = PE,Xarrow_forwardConsider three particles: qa = 3e, qB -2e, and qc -4e that are each placed a distance d =4.4 µm from the origin, as shown in the figure below. y 9c = -4e d d + 9A = 3e d ¶B = -2e What is the total electric potential at the origin? Provide your answer in millivolts with the precision of three places after decimal.arrow_forwardThe charge density on a disk of radius R = 13.0 cm is given by a = ar, with a = 1.44 µC/m³ and r measured radially outward from the origin (see figure below). What is the electric potential at point A, a distance of 34.0 cm above the disk? Hint: You will need to integrate the nonuniform charge density to find the electric potential. You will find a table of integrals helpful for performing the integration. V R Aarrow_forward
- In (Figure 1), 91 = +2.5 nC and 92 = -2.0 nC, and the side length of the square is 0.15 m. Figure 91 92 Part A What is the electric potential at point A? Express your answer to two significant figures and include appropriate units. Value Submit на Part B S μÅ Value Request Answer C Units What is the electric potential at point B? Express your answer to two significant figures and include appropriate units. Units P Pearson ? ?arrow_forwardA parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that ℓ ≫ d. A parallel-plate capacitor is comprised of two square plates with sides of length ℓ and separation distance d. There are three dielectric materials in the space between the capacitor plates. A material with length ℓ⁄2, height d, and dielectric constant ?1 fills the left half of the space. A material with length ℓ⁄2, height d⁄2, and dielectric constant ?2 fills the top right quarter of the space. A material with length ℓ⁄2, height d⁄2, and dielectric constant ?3 fills the bottom right quarter of the space. (a) Find an expression for the capacitance of the device in terms of the plate area A and d, ?1, ?2, and ?3. (Use the following as necessary: ?1, ?2, ?3, ?0, A and d.)C = (b) Calculate the capacitance using the values A = 1.30 cm2, d = 2.00 mm, ?1 = 4.90, ?2 = 5.60, and ?3 = 2.50.arrow_forwardImagine three concentric spherical conductive shells of radii 5 cm, 10 cm, and 15 cm charged with 4 µC, 11 µC, and -15 µC, respectively. What is the electric field at r=1.4 cm, r=12 cm, and r=21.8 cm? V/m, Enter an exact number. E1 = E2= V/m, E3= V/m. What are the electric potentials at these points? V1 = V, V2= V, V3= V.arrow_forward
- Three capacitors are connected as shown, where C = 0.045 F. A. Input an expression for the equivalent capacitance between points a and b, in terms of C. B. What is the capacitance, in farads? C. If the capacitors are charged with a ΔV = 10 V source, how much energy will the circuit store, in joules?arrow_forwardThe figure below is a graph of an electric potential as a function of position. A function is plotted on a coordinate plane with horizontal axis x and vertical axis V. Points A and B lie on the +x-axis, where A is closer to the origin. The function starts in quadrant 3, curves up and right to reach a local maximum at the origin, then curves down and right to reach a local minimum in quadrant 4. It then curves up and right, crosses the x-axis to the left of point A, and reaches its maximum value directly above point B. The function then curves down and right, crosses the x-axis, and continues until it exits the viewing window in quadrant 4. If a positively-charged particle is released from rest at point A, what will be its subsequent motion?The positively-charged particle will... oscillate around point B. remain at point A. move to the right. move to the left.arrow_forwardThe voltage across a capacitor is given by the formula V=Q/C, where Q is usually called "the charge on the capacitor." Where is this charge in a capacitor? Does the capacitor really have a net charge?arrow_forward
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