
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Transcribed Image Text:As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m x 2.0 m has a
charge of 8.0 x 10-11 C distributed uniformly throughout its volume. Use Gauss's law to
determine the electric field at point P, which is located within the slab beneath its center, 1.0
mm from one of the faces. (e0 = 8.85 × 10-12 C2/N • m²)
1.00 mm
P.
5.00
1.
mm
2.00 m
O 34 N/C
14 N/C
23 N/C
O 0.68 N/C
O 57 N/C
Expert Solution

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Step 1
Let us the total flux pass through both faces 2A = 2 dx dy of gaussian box 2 dx dy dz.
The electric flux is parallel to the z-axis only,
According to gauss's law
Flux = E.2A
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