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As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m x 2.0 m has a charge of 8.0 × 10-11 C distributed uniformly throughout its volume. Use Gauss's law to determine the electric field at point P, which is located within the slab beneath its center, 1.0 mm from one of the faces. (0 = 8.85 × 10-12 C2/N • m2)

As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m x 2.0 m has a charge of 8.0 × 10-11 C distributed uniformly throughout its volume. Use Gauss's law to determine the electric field at point P, which is located within the slab beneath its center, 1.0 mm from one of the faces. (0 = 8.85 × 10-12 C2/N • m2)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m x 2.0 m has a charge of 8.0 x 10-11 C distributed uniformly throughout its volume. Use Gauss's law to determine the electric field at point P, which is located within the slab beneath its center, 1.0 mm from one of the faces. (e0 = 8.85 × 10-12 C2/N • m²) 1.00 mm P. 5.00 1. mm 2.00 m O 34 N/C 14 N/C 23 N/C O 0.68 N/C O 57 N/C
Transcribed Image Text:As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m x 2.0 m has a charge of 8.0 x 10-11 C distributed uniformly throughout its volume. Use Gauss's law to determine the electric field at point P, which is located within the slab beneath its center, 1.0 mm from one of the faces. (e0 = 8.85 × 10-12 C2/N • m²) 1.00 mm P. 5.00 1. mm 2.00 m O 34 N/C 14 N/C 23 N/C O 0.68 N/C O 57 N/C
Expert Solution
Step 1

Let us the total flux pass through both faces 2A = 2 dx dy of gaussian box 2 dx dy dz.

 

The electric flux is parallel to the z-axis only,

 

According to gauss's law

 

Flux = E.2A

Flux = Qenclosedε0          =ρ. volε0          =E 2dx.dy              =ρ.dx.dy.dzε0          = ρ.dzε0

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